Answer:
a) X[bar]₁= 1839.20 cal
b) X[bar]₂= 1779.07 cal
c) S₁= 386.35 cal
Step-by-step explanation:
Hello!
You have two independent samples,
Sample 1: n₁= 15 children that did not eat fast food.
Sample 2: n₂= 15 children that ate fast food.
The study variables are:
X₁: Calorie consumption of a kid that does not eat fast food in one day.
X₂: Calorie consumprion of a kid that eats fast food in one day.
a)
The point estimate of the population mean is the sample mean
X[bar]₁= (∑X₁/n₁) = (27588/15)= 1839.20 cal
b)
X[bar]₂= (∑X₂/n₂)= (26686/15)= 1779.07 cal
c)
To calculate the sample standard deiation, you have to calculate the sample variance first:
S₁²= 
[∑X₁² - (( ∑X₁)²/n₁)]= 
= 149263.4571 cal²
S₁= 386.35 cal
I hope it helps!
Answer:
a. Simple interest = $174
b. Compund interest = $1187.1
Step-by-step explanation:
Given the following data;
Principal, P = $1000
Interest, R = 2.9%
Time, T = 6 months
a. To find the simple interest;
S.I = (PRT)/100
S.I = (1000*2.9*6)/100
S.I = 17400/100
S.I = $174
b. To find the compound interest;
Substituting into the formula, we have;
A = $1187.1
Answer:
Cosa/2-tana+sina
Step-by-step explanation:
Cosatana
A research paper recommends using Poisson process to model the number of failures in commercial water pipes The paper also gives estimates the failure rate in units of failures per 100 miles of pipe per day; for four different types of pipe and for many different years_ For example, for cast iron pipe in 2005, the authors' estimate is the failure rate is 0.0864 failures per 100 miles per day: Suppose a town had 2500 miles of cast iron pipe underground in 2005 What is the probability of at least two failures
