a newspaper reports that in urban area the average price of new homes had decreased, but the number sold had increased. The sita
1 answer:
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Answer:
[a]. 10560, [b]. 14160, [c]. 7668.
Explanation:
[a]. In order to be able to solve this particular question we have to consider what is known as LINEAR PROGRAMMING.
We have the assumption that the function to be equals to 10A + 9B. The first step that we need to take here is to find the constraint for the linear programming relaxation which is;
1/2A + 5/6B 600.
1/10A + 1/4B 135. Thus, A
0 and B
With the help of excel solver and graphs, that we have the profit at $18 we are going have the value of A =300 and B =420. Therefore, the optimal solution = [300,420].
Thus, we have the objective function value to be = 10,560. [that is 10 * 300 + 420 * 18}.
[b]. For option b, where the profit increases to $20, the optimal solution lies on A =708 and B =0. Hence, objective function value = 14,160[ that is 20 * 708 + 0].
[c]. Here, there is increase in the sewing operation capacity to 750 hours. Therefore, we will have the value of A = 540 and B = 252.
Thus, the objective function value = 7668.
Answer:
Step wise detailed solution is given in the attached diagram
Answer:
- The final temperature in the container with Gold is 27.49 ⁰C
- The final temperature in the container with Iron is 33.01 ⁰C
Therefore, the highest final temperature is obtained in the container with Iron.
Explanation:
Q = mcΔT
Where;
Q is the quantity of heat gained or lost
m is the mass of the metals or water
c is the specific heat capacity
ΔT is the change in temperature, T₂ - T₁
T₂ is the final temperature and T₁ is the initial temperature
Heat lost by metals at 100°C is equal to heat gained by water at 25°C
Specific heat capacity of water = 4.18 J/g°C
Specific heat capacity of gold = 0.129 J/g°C
Specific heat capacity of iron = 0.45 J/g°C
⇒For Gold
-20*0.129*(T₂ - 100) = 18*4.18 (T₂ - 25)
-2.58T₂ +258 = 75.24T₂ - 1881
77.82T₂ = 2139
T₂ = 2139/77.82
T₂ = 27.49 ⁰C
⇒For Iron
-20*0.450*(T₂ - 100) = 18*4.18 (T₂ - 25)
-9T₂ +900 = 75.24T₂ - 1881
84.24T₂ = 2781
T₂ = 2781/84.24
T₂ = 33.01 ⁰C
Therefore, the highest final temperature is obtained in the container with Iron.