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-BARSIC- [3]
2 years ago
11

Write a brief summary about similar figures

Mathematics
2 answers:
Darina [25.2K]2 years ago
5 0

Similar figures are the same shape but not the same size. you can find out the scale by using parallel lines.

Anna11 [10]2 years ago
3 0

Answer:

*You could just look it up.

Here's what I found on google:

Two figures are said to be similar if they are the same shape. In more mathematical language, two figures are similar if their corresponding angles are congruent, and the ratios of the lengths of their corresponding sides are equal. This common ratio is called the scale factor.

So basically, similar figures are 2 figures that are the same shape.

They don't have to be the same size.

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Bruce added some chlorine to the water in a pool. The chlorine evaporated at a fixed rate every week. The table below shows the
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The answer is F(n)=54 (0.5)^(n-1)
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15:7.5:30
This is because 15 is the smallest, which is half of 4(30). And right between 15 and 30 is 7.5.

Hope this helps
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Sofia is driving to Texas. She travels at 70 kilometers per hour for 2 hours, and 63 kilometers per hours for 5 hours. Over 7 ho
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Answer:

65 kph

Step-by-step explanation:

There were a total of 7 hours. So two hours were at 70 and the other 5 hours at 63: the equation would be: (70+70+63+63+63+63+63)/7=65

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3 years ago
7. Use the quadratic formula to find the solution(s). x² + 2x - 8 = 0​
morpeh [17]

Hey there!

<u>Use the quadratic formula to find the solution(s). x² + 2x - 8 = 0</u>

  • Answer :

x = -4 or x = 2 ✅

  • Explanation :

<em><u>Quadratic</u></em><em><u> </u></em><em><u>formula </u></em><em><u>:</u></em><em><u> </u></em>ax² + bx + c = 0 where a ≠ 0

The number of real-number solutions <em>(roots)</em> is determined by the discriminant (b² - 4ac) :

  • If b² - 4ac > 0 , There are 2 real-number solutions

  • If b² - 4ac = 0 , There is 1 real-number solution.

  • If b² - 4ac < 0 , There is no real-number solution.

The <em><u>roots</u></em> of the equation are determined by the following calculation:

x =  \frac{ - b \pm  \sqrt{ {b}^{2} - 4ac } }{2a}

Here, we have :

  • a = 1
  • b = 2
  • c = -8

1) <u>Calculate </u><u>the </u><u>discrim</u><u>i</u><u>n</u><u>ant</u><u> </u><u>:</u>

b² - 4ac ⇔ 2² - 4(1)(-8) ⇔ 4 - (-32) ⇔ 36

b² - 4ac = 36 > 0 ; The equation admits two real-number solutions

2) <u>Calculate </u><u>the </u><u>roots </u><u>of </u><u>the </u><u>equation</u><u>:</u>

▪️ (1)

x_1 =  \frac{ - b -  \sqrt{ {b}^{2}  - 4ac} }{2a}  \\  \\ x_1 =  \frac{ - 2 -  \sqrt{36} }{2(1) }  \\  \\ x_1 =  \frac{ - 2 - 6}{2}   \\ \\ x_1 =  \frac{ - 8}{2}  \\  \\ \blue{\boxed{\red{x_1 = -4}}}

▪️ (2)

x_2 =  \frac{ - b  +   \sqrt{ {b}^{2} - 4ac } }{2a}  \\  \\ x_2 =  \frac{ - 2 +  \sqrt{36} }{2(1)}  \\  \\ x_2 =  \frac{ - 2 + 6}{2}  \\  \\ x_2 =  \frac{4}{2}  \\  \\ \red{\boxed{\blue{x_2 = 2}}}

>> Therefore, your answers are x = -4 or x = 2.

Learn more about <u>quadratic equations</u>:

brainly.com/question/27638369

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*ANSWER PLS TYY* Which of the following statements is TRUE about finding the area of a polygon? a.) You can use a coordinate pla
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Answer:

The answer to this question is b)

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