Answer:
Step-by-step explanation:
Since the cross section is uniform, the depth of the water is irrelevant. The rate of change of height is the rate of change of volume divided by the area.
dh/dt = (dV/dt)/(π·r²)
= (9 ft³/min)/(π·(3 ft)²)
= 1/π ft/min ≈ 0.3813 ft/min
tan t is negative in quadrant IV and positive in quadrants 1 / 3
