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Rama09 [41]
3 years ago
11

Plz help... need it quick

Mathematics
1 answer:
erik [133]3 years ago
4 0

Answer:

id say the big triangle and the rectangle

Step-by-step explanation:

sorry if im wrong

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a

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4 0
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What is the radius of a circle whose equation is x2 y2 8x – 6y 21 = 0?
andrew11 [14]

we know that

the standard form of the equation of the circle is

(x-h)^{2} +(y-k)^{2}=r^{2}

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x^{2} +y^{2} +8x-6y+21=0

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Group terms that contain the same variable, and move the constant to the opposite side of the equation

(x^{2}+8x) +(y^{2}-6y)=-21

Complete the square twice. Remember to balance the equation by adding the same constants to each side.

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Rewrite as perfect squares

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the center of the circle is (-4,3)

the radius of the circle is 2\ units

therefore

<u>the answer is</u>

the radius of the circle is 2\ units


8 0
3 years ago
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Step-by-step explanation:

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