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IrinaK [193]
2 years ago
8

What is 3 3/5 + 6 3/10

Mathematics
1 answer:
Yanka [14]2 years ago
7 0

Answer:

18/5 or 3 3/5

Step-by-step explanation:

You might be interested in
Which transformations to the graph of j(x) would result in the graph of j(4x) – 27?
Grace [21]

Answer:

Option D.

Step-by-step explanation:

It is given that, graph of j(x) transformed in the graph of j(4x) – 27.

We need to find the transformations.

Consider the new function is

f(x)=j(4x)-27          ... (1)

The translation is defined as

f(x)=j(kx+a)+b                ... (2)

Where, k is stretch factor, a is horizontal shift and b is vertical shift.

If 0<k<1, then the graph stretched horizontally by factor of 1/k and if k>1, then the graph compressed horizontally by factor of 1/k.

If a>0, then the graph shifts a units left and if a<0, then the graph shifts a units right.

If b>0, then the graph shifts b units up and if b<0, then the graph shifts b units down.

On comparing (1) and (2), we get

k=4>1, the graph j(x) compressed horizontally by factor of 1/4.

a=0, so there is no horizontal shift.

b=-27<0, so the graph of j(x) shifts 27 units down.

So, the required transformations are horizontal compression by a factor of 1/4, and a translation 27 units down.

Therefore, the correct option is D.

6 0
2 years ago
Look at this graph:
Black_prince [1.1K]

Answer:

3/2

Step-by-step explanation:

slope=rise/run=30/20=3/2

3 0
2 years ago
Find KL. Round to the nearest hundredth.<br> d<br> Sut of<br> .1.3<br> 48<br> L
VARVARA [1.3K]

Answer:

1.3

Step-by-step explanation:

give brainliest

4 0
2 years ago
5. Write down the nth term of each of the following G.Ps
yawa3891 [41]

Answer:

1i) nth term = 12(-b/4)^(n-1)

ii) nth term = 3(-1/9)^(n-1)

2i) Sixth term= (-3b^5)/256

ii) Eight term = -1/1594323

Question:

The complete question as found on brainly (question-10746111):

Write down the nth term of each of the following G.Ps whose first two terms are given as follows. Also find the term stated besides each G.P.

i) 12,-3b,......sixth term

ii) 3,-1/3,..........;8th term?

Step-by-step explanation:

1) To solve terms involving Geometric progressions (GPs), we would first state the variables that are to be incorporated in the formula.

i) 12,-3b,......;sixth term

1st term = a= 12

r = common ratio = 2nd term /1st term

r = -3b/12 = -b/4

Then we would find the nth term

See attachment for details

ii) 3,-1/3,..........;8th term

1st term = a= 3

r = common ratio = 2nd term /1st term

r = (-⅓)/3 = (-⅓)(⅓) = -1/9

Then we would find the nth term

See attachment for details

2) we are to determine the sixth term in (i) and eight term in (ii)

See attachment for details

Sixth term= (-3b^5)/256

Eight term = -1/1594323

7 0
3 years ago
NEED HELP URGENT!! How do I solve this on number 30?(please go through the steps)
tatiyna

x^2+6x-5=0

x^2=2x

2x+6x-5=0

2x+6x=8x

8x-5=0

+5 +5

(if you don’t know what I’m doing here is that I’m removing the negative 5 by putting a positive 5 since both of them make 0. Also the “x” always stay alone and the unit stays as the unit)

(I putted the positive under the 0 because what u do to the unit you need to do the same thing with the other.)

8x/8=5/8

(If ur lost here it means dividing.)

The answer

X=0.625

(btw I’m not really sure if this is right so um don’t really trust me in this lol)

3 0
3 years ago
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