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ratelena [41]
3 years ago
11

30 points!!! √8+√98+√32.​

Mathematics
2 answers:
frez [133]3 years ago
6 0

Let us first resolve the given numbers into prime factors.

By prime factorization,

\longmapsto √8 = √( <u>2 × 2</u> × 2)

\longmapsto √8 = 2√2

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

\longmapsto √98 = √( 2 × <u>7 × 7</u>)

\longmapsto √98 = 7√2

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

\longmapsto √32 = √(<u> 2 × 2 </u>×<u> 2 × 2 </u>× 2)

\longmapsto √32 = 2 × 2√2

\longmapsto √32 = 4√2

<u>Accordi</u><u>ng</u><u> to</u><u> the</u><u> question</u><u>,</u>

\longmapsto √8+√98+√32

\longmapsto 2√2 + 7√2 + 4√2

  • Taking √2 as common.

\longmapsto √2(2 + 7 + 4)

\longmapsto √2(13)

\longmapsto 13√2

<u>So</u><u>,</u><u> </u><u>we</u><u> </u><u>get</u><u> </u><u>that</u><u> </u><u>:</u>

<h3>√8+√98+√32 → 13√2</h3>

yanalaym [24]3 years ago
5 0

Answer:

13√2 or 18.38478

Step-by-step explanation:

i hope this helps :)

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Answer:

Step-by-step explanation:

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(8x²-18x+10)=(x²+5)A+(x-3)(bx+c)

8x²-18x+10= x²A+5A+bx²+cx-3bx-3c

combine like terms:

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(8x²-18x+10)

looking at the equation

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(8x²-18x+10)/[(x^2+5)(x-3)] =A/x-3 +(bx+c)/x²+5

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(8x²-18x+10)/[(x^2+5)(x-3)] =

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(4x+2)/[(x²+4)(x-2)]

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follow the same step in the previous answer:

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Step-by-step explanation:

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Answer:

Step-by-step explanation:

Given that the height in  inches, of a randomly chosen American woman is a normal random variable with mean μ = 64 and variance 2 = 7.84.

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