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3 years ago

Help geometry! Will give brainly! :)

Mathematics

1 answer:

victus00 [196]3 years ago

7 0

Answer:

6.5

Step-by-step explanation:

I might be wrong, I'm so sorry if I am! I'm not the best at geometry

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Which expression is equivalent to (9.5 × 105) – (2.3 × 104)?

Vedmedyk [2.9K]

997.5-239.2

hope this helped :)

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3 years ago

Identify the natural number that is closest to 4–√. 2 3 1 4

Minchanka [31]

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3 years ago

A verbal phrase for 6n-4 is

Savatey [412]

A verbal phrase for 6n-4 is the difference of 6 times a number and 4

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4 years ago

739 rounded to the nearest hundred

aliya0001 [1]

700, hope that helped you! have a good day

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3 years ago

A certain country has $10 billion in paper currency in circulation, and each day $50 million comes into the country's banks. The

mash [69]

Answer:

$\bf x(t)=10(1-e^{-0.005*t})$

Step-by-step explanation:

The differential equation

$\bf \displaystyle\frac{dx}{dt}=0.005(10-x)$

can be solved by separation of variables. Write the equation as

$\bf \displaystyle\frac{dx}{10-x}=0.005dt$

Integrate on both sides

$\bf \int\displaystyle\frac{dx}{10-x}=\int0.005dt\Rightarrow -ln(10-x)=0.005t+C\Rightarrow\\\\\Rightarrow ln(10-x)^{-1}=0.005t+C\Rightarrow (10-x)^{-1}=e^{0.005t}e^C$

where C is a constant.

$\bf e^C$ is also a constant and we will keep calling it C, (there is no reason to change the letter). We have then

$\bf (10-x)^{-1}=Ce^{0.005t}\Rightarrow \displaystyle\frac{1}{10-x}=Ce^{0.005t}\Rightarrow 10-x=\displaystyle\frac{1}{Ce^{0.005t}}\Rightarrow\\\\\Rightarrow x(t)=10-(1/C)e{-0.005t}$

(1/C) is a constant, and for the same reason we will keep calling it C. So the general solution is

$\bf x(t)=10-Ce^{-0.005t}$

Now, we use the initial condition x(0)=0

$\bf x(0)=10-Ce^{-0.005*0}=0\Rightarrow C=10$

and the particular solution is

$\bf x(t)=10-10e^{-0.005*t}=10(1-e^{-0.005*t})\\\\\boxed{x(t)=10(1-e^{-0.005*t})}$

7 0

3 years ago