Is This Substitution?
Cause if it is, then Y = 3x - 4
Y = 4 + x
= (4, 8)
Step-by-step explanation:
15=2c+7
15-7=2c
8=2c
8/2=c
4=c
c=4
Your slope of this graph is: 4/3x
A turning point occurs when the velocity is equal to zero, but the acceleration is not equal to zero.
t(x)=(x+5)^3+7
dt/dx=3(x+5)^2
d2t/dx2=6(x-5)
dt/dx=0 only when x=-5
However, since d2t/dx2(-5)=0, this point is an inflection point, not a turning point.
So there is no turning point for this function.
Now in this problem, it is even easier than the above to show that there is no turning point. A turning point by definition is when the derivative or velocity changes sign. Since in this case v=3(x+5)^2, for any value of x, v≥0, and thus never becomes negative, so it never changes from a positive to negative velocity because velocity in this instance is a squared function.
Answer:
c) (-2, 1)
Step-by-step explanation:
3x - 3y = -9
2x + y = -3
2x + y = -3
-2x -2x
y = -2x - 3
3x - 3y = -9
y = -2x - 3
3x - 3(-2x - 3) = -9
3x + 6x + 9 = -9
9x + 9 = -9
- 9 -9
9x = -18
/9 /9
x = -2
y = -2x - 3
y = -2(-2) -3
y = 4 - 3
y = 1
(x, y) --> (-2,1)
Check your answer:
y = -2x - 3
1 = -2(-2) - 3
1 = 4 - 3
1 = 1
This statement is true
Hope this helps!
