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3 years ago

8

X+2x÷y-2y; x=4, y=-2

2 answers:

Nookie1986 [14]3 years ago

5 0

Substitute the value of the variable into the expression and simplify.

4

Hatshy [7]3 years ago

4 0

4 but make sure to show all calculations ^

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For the equation -4y = 8x , what is the constant of variation?

Inga [223]

-4y = 8x

Divide both sides by -4

y = -2x

This is in the form of y = kx, where k is the constant of variation.
y = kx is the direct

That means, k = -2.

The constant of variation is B. -2.

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3 years ago

Solve the following quadratic equations by any method. The solutions are:

Nataly_w [17]

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Option C .

Step-by-step explanation:

We would like to solve the below <u>quadratic </u><u>equation</u><u> </u>,

$\longrightarrow f(x) = x^2-12x +32$

Step 1 : <u>E</u><u>q</u><u>u</u><u>a</u><u>t</u><u>e</u><u> </u><u>f</u><u>(</u><u>x</u><u>)</u><u> </u><u>w</u><u>i</u><u>t</u><u>h</u><u> </u><u>0</u><u> </u><u>:</u><u>-</u>

$\longrightarrow f(x) = 0\\$

$\longrightarrow x^2-12x + 32=0$

Step 2 : <u>F</u><u>a</u><u>c</u><u>t</u><u>o</u><u>r</u><u>i</u><u>s</u><u>e</u><u> </u><u>t</u><u>h</u><u>e</u><u> </u><u>R</u><u>H</u><u>S</u><u> </u><u>:</u><u>-</u>

$\longrightarrow x^2-8x - 4x +32=0\\$

$\longrightarrow x(x-8)-4(x-8)=0\\$

$\longrightarrow (x-8)(x-4)=0\\$

Step 3 : <u>E</u><u>q</u><u>u</u><u>a</u><u>t</u><u>e</u><u> </u><u>e</u><u>a</u><u>c</u><u>h</u><u> </u><u>f</u><u>a</u><u>c</u><u>t</u><u>o</u><u>r</u><u> </u><u>w</u><u>i</u><u>t</u><u>h</u><u> </u><u>0</u><u> </u><u>:</u><u>-</u>

$\longrightarrow x - 8 = 0\\ \qquad x -4=0$

$\longrightarrow x = 8 \qquad x = 4$

$\longrightarrow \underline{\underline{\boldsymbol{ x = 8,4}}}$

<u>H</u><u>e</u><u>n</u><u>c</u><u>e</u><u> </u><u>o</u><u>p</u><u>t</u><u>i</u><u>o</u><u>n</u><u> </u><u>C</u><u> </u><u>i</u><u>s</u><u> </u><u>c</u><u>o</u><u>r</u><u>r</u><u>e</u><u>c</u><u>t</u><u> </u><u>.</u>

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2 years ago