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butalik [34]
3 years ago
8

For what value of x must ABCD be a parallelogram?

Mathematics
1 answer:
Svetach [21]3 years ago
4 0

Answer:

x  = 3

Step-by-step explanation:

to be a parallelogram opposite sides have to be equal

so we have

DC = AB\\\\20x-7 = 16x+5

now solve for x

20x-7+7 = 16x+5+7\\\\20x = 16x + 12\\\\20-16x = 16x+12-16x\\\\4x = 12\\\\x = \frac{12}{4} = 3

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Kennedy had the expression 3(2x-3x+8). She simplified and rewrote the
Sati [7]

Answer:

It is -3x+24

Step-by-step explanation:

2x-3x is -x or -1x

It can also be simplified further using multiplication.

3(2x-3x+8)

3(-x+8)

-3x+24

7 0
3 years ago
Sing the quadratic formula to solve x2 + 20 = 2x, what are the values of x?
Elden [556K]

Answer:

x = 1 ± i √ 19

Step-by-step explanation:

x = 1 ± i √ 19

8 0
3 years ago
Find Horizontal and Vertical Asymptotes for y=(1)/((x+2)^3)
Usimov [2.4K]

Answer:

Vertical asymptote: x = -2

Horizontal asymptote: y = 0 or x axis.

Step-by-step explanation:

The rational function is given as:

y=\frac{1}{(x+2)^3}

Vertical asymptotes are those values of x for which the function is undefined or the graph moves towards infinity.

For a rational function, the vertical asymptotes can be determined by equating the denominator equal to zero and finding the values of x.

Here, the denominator is (x+2)^3

Setting the denominator equal to zero, we get

(x+2)^3=0\\(x+2)=0\\x=-2

Therefore, the vertical asymptote occur at x=-2.

Horizontal asymptotes are the horizontal lines when x tends towards infinity.

For a rational function, if the degree of numerator is less than that of the denominator, then the horizontal asymptote is given as y=0.

Here, there is no x term in the numerator. So, degree is 0. The degree of the denominator is 3. So, the degree of numerator is less than that of denominator.

Therefore, the horizontal asymptote is at y=0 or x axis.

3 0
3 years ago
A sine function can be used to model light waves. Green light has a wave length, or period of about 520 nm. Which equation best
White raven [17]

Answer:

y = A sin (kx \pm wt)

Where k represent the number of wave k =\frac{2\pi}{\lambda} and w =\frac{2\pi}{T} represent the angular frequency with T the period.

For this case we know tha T = 520 nm

And the angular frequency would be given by:

w = \frac{2\pi}{520}= \frac{pi}{260}

So then the possible anwer for this case would be:

D.) y= sin pi/260 theta

Since is the only option with satisfy the general equation of a wave.

Step-by-step explanation:

Since the sine function can be used to model light waves we can use the following general expression:

y = A sin (kx \pm wt)

Where k represent the number of wave k =\frac{2\pi}{\lambda} and w =\frac{2\pi}{T} represent the angular frequency with T the period.

For this case we know tha T = 520 nm

And the angular frequency would be given by:

w = \frac{2\pi}{520}= \frac{pi}{260}

So then the possible anwer for this case would be:

D.) y= sin pi/260 theta

Since is the only option with satisfy the general equation of a wave.

4 0
4 years ago
16
Papessa [141]

.16666667 is your answer u have to round up the last number tho

6 0
3 years ago
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