Answer:
zero goats and 120 Ilamas to get profit of $15,120
Step-by-step explanation:
Goats: G
Ilamas: l
Explicit constraints:
2G + 5l ≤ 400
100G+ 80l≤ 13,200
Implicit constraints
G≥0
I≥0
P= 84G+ 126l
See attachment for optimal area
substituting coordinats of optimal region in profit equation to get profit
When G= 132, l=0
P=84(132) + 126(0)
P=11,088
When G=0, l=120
P=84(0)+ 126(120)
P = 15120
When G= 100, l=40
P=84(100)+126(40)
P=13440
Answer:
Curved surface area of a cone =πrl.
3.142×8×15=377.04cm
tried to do it on text but It was pretty hard
9514 1404 393
Answer:
4/5 acre
Step-by-step explanation:
We assume your allocations are ...
goats: 3/5 acre
pigs: 1/5 acre
llamas: 2/5 acre
2 acres is 10/5 acres, so the remaining area is ...
10/5 -3/5 -1/5 -2/5 = (10 -3 -1 -2)/5 = 4/5
4/5 acre is allocated to horses.
Direct variation is y=kx, inverse variation is y=k/x....
-5y=-2x divide both sides by -5
y=2.5x
So this is a direct variation with a constant of 2.5
