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Mademuasel [1]
3 years ago
9

Write the quadratic function in the form g(x) = a(x-h)^2 +k

Mathematics
1 answer:
LenKa [72]3 years ago
3 0

Answer:

the ansswer is 3x+4x=24

Step-by-step explanation:

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the answers would be: A, C, and E

Step-by-step explanation:

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Is the line segment 4x+2y=0 parallel?
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4x + 2y = 0
2y = -4x 
y = -2x...the slope here is -2

the above line ^^ is parallel to y = -2x + 3.....because parallel lines will have the same slope

7 0
4 years ago
5. The sum of two integers is (-8). Their product is (+7). What are the two<br> integers?
egoroff_w [7]

Answer:

Step-by-step explanation:

Let one number = x

The other  number = (-8) - x

Their product  = 7

x*( -8 - x) = 7

x*(-8) - x*x = 7

-8x - x² = 7

0 = 7 + 8x + x²

x² + 8x + 7 = 0

x² + 7x +x +7 = 0

x(x + 7) + (x+7) = 0

(x + 7)(x + 1) = 0

x + 7 = 0   ;x + 1 = 0

x = -7         ; x = -1

The two integers are: (-7) and (-1)

6 0
3 years ago
A survey reports that 67% of college students prefer to drink more coffee during the exams week. If we randomly select 80 colleg
Akimi4 [234]

Answer:

The probability that at most 50 say that they drink coffee during exam week is 0.166.

Step-by-step explanation:

The random variable <em>X</em> can be defined as the number of college students who prefer to drink more coffee during the exams week.

The probability of the random variable <em>X</em> is <em>p</em> = 0.67.

A random sample of <em>n</em> = 80 college students are selected.

The response of every students is independent of the others.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> = 80 and <em>p</em> = 0.67.

But the sample selected is too large and the probability of success is close to 0.50.

So a Normal approximation to binomial can be applied to approximate the distribution of X if the following conditions are satisfied:

  1. np ≥ 10
  2. n(1 - p) ≥ 10

Check the conditions as follows:

np=80\times 0.67=53.6>10\\n(1-p)=80\times (1-0.67)=26.4>10

Thus, a Normal approximation to binomial can be applied.

X\sim N(np, np(1-p))

The mean of the distribution of <em>X</em> is:

\mu=np=80\times 0.67=53.6

The standard deviation of the distribution of <em>X</em> is:

\sigma=\sqrt{np(1-p)}=\sqrt{80\times 0.67\times (1-0.67)}=4.206

A Normal distribution is a continuous distribution. So, the probability at a point cannot be computed for the Normal distribution. To compute the probability at a point we need to apply the continuity correction.

Compute the probability that at most 50 say that they drink coffee during exam week as follows:

Apply continuity correction:

P(X\leq 50)=P(X

                 =P(X

*Use a <em>z</em>-table for the probability.

Thus, the probability that at most 50 say that they drink coffee during exam week is 0.166.

5 0
3 years ago
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