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nasty-shy [4]
3 years ago
6

Sorry if you can't see it correctly !! the question is-

Mathematics
2 answers:
Anna35 [415]3 years ago
8 0
So you would put 9 in for both of the D’s . Which would be 3(9) + 9^2. You will simply it and it’ll be 27+81 which is 108. THE ANSWER IS 108
Rzqust [24]3 years ago
3 0

–28

Step-by-step explanation:

9 + 3(10 ÷ 2) – 52

Solve parentheses first: 9 + 3(5) – 52

Order of Operations says to solve multiplication next: 9 + 15 – 52  

Simplify the addition: 24 – 52

Subtract 52 – 24 and negate the answer: –28

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Math problem help me
Ratling [72]

Answer:

y=3x+2

Step-by-step explanation:

To find the equation, use the slope-intercept formula:

y=mx+b

m is the slope and b is the y-intercept. Now, it'll really help to draw a line through the points, connecting them. If you look at point (0,2), we can see that this is the y-intercept (where a point sits on the y-axis when x=0). You can insert this into the equation by taking the y value:

(0,2)\\y=mx+2

Now, take any two points to find the slope. To make it easier, I'll use (1,5) and (0,2). Use the slope formula for when you know two points:

\frac{y(2)-y(1)}{x(2)-(x1)} =\frac{rise}{run}

Rise over run is the change in the y-axis over the change in the x-axis. Insert values:

(1(x1),5(y1))\\(0(x2),2(y2))\\\\\frac{2-5}{0-1}

Solve:

\frac{2-5}{0-1}=\frac{-3}{-1}

Since both are negative, the result is a positive:

\frac{-3}{-1}=\frac{3}{1} =3

Insert this into the equation as m, the slope:

y=3x+2

Done.

6 0
3 years ago
4 of 10
Alexus [3.1K]

Answer:

foodgnfnfnfd2vefvf3vedvwf wsvwsv

7 0
3 years ago
A freshly prepared sample of curium-243 undergoes 3312 disintegrations per second. after 6.00 yr, the activity of the sample dec
Lerok [7]

I took the liberty of finding for the complete question. And here I believe that the problem asks for the half life of Curium. Assuming that the radioactive decay of Curium is of 1st order, therefore the rate equation is in the form of:

A = Ao e^(-kt)

where,

A = amount after t years = 2755

Ao = initial amount = 3312

k = rate constant

t = number of years passed = 6

 

Therefore the rate constant is:

2755/3312 = e^(-6k)

-6k = ln (2755/3312)

k = 0.0307/yr

 

The half life, t’, can be calculated using the formula:

t’ = ln 2 / k

Substituting the value of k:

t’ = ln 2 / 0.0307

t’ = 22.586 years

or

t’ = 22.6 years

4 0
3 years ago
What is the height of the building pictured below if its shadow is 100 ft. long?
Evgen [1.6K]
Yeah.. baby, do the SOH CAH TOA with the hula hoop

\bf 
sin(\theta)=\cfrac{opposite}{hypotenuse}
\qquad \qquad 
% cosine
cos(\theta)=\cfrac{adjacent}{hypotenuse}

\\ \quad \\
% tangent
tan(\theta)=\cfrac{opposite}{adjacent}


so.. hmmm we have in the picture, an angle, and two sides,
actually, is the "adjacent" side, and the "opposite"

so.. which  of those ratios give us only
the angle
the adjacent side
the opposite side?

ahhha!, is Ms tangent
so  \bf tan(\theta)=\cfrac{opposite}{adjacent}\implies tan(42^o)=\cfrac{h}{100}

solve for "h"

5 0
3 years ago
a merchant is selling wind chimes from a booth at the flea market. He rents his space for 125$ per day. The profit from each win
serious [3.7K]
Let n be the number of minimum chimes needed.

$3500=$12n-$125x5
$4125=$12n
5 0
3 years ago
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