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lutik1710 [3]
3 years ago
9

!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics
1 answer:
Sergio [31]3 years ago
7 0

Answer:

false

Step-by-step explanation:

15²+30² =  225+900 = 1125

35² = 1225

Since Pythagoras theorem doesn't hold for this triangle, it is not a right triangle.

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Can someone PLEASE help me. No one will answer the question completely smh
Vesna [10]

Ok got it. If you have any questions just ask in the chat below :)

8 0
3 years ago
Anthony deposited $14,000 with a bank in a 5-year certificate of deposit yielding 6% compounded daily. Find the compound amount
Mnenie [13.5K]

Answer:

Total = 14,000 * 1 + (.06 / 365) ^365*5

Total = 14,000 * 1.0.000164383561643836^1,825

Total = 14,000 * 1.3498255274

Total = 18,897.56

Step-by-step explanation:

8 0
3 years ago
Solve Ax-By=c for y how do you solve this
Rainbow [258]

Answer:

y = - c/B + Ax/B

Step-by-step explanation:

Isolate the variable by dividing each side by factors that don't contain the variable.

5 0
3 years ago
I need this ASAP!!
Free_Kalibri [48]

Answer:

n = 4752 gallons

Step-by-step explanation:

Given

Dilivery: 396 dozen gallon in a day

RequirEd

determine the number of the gallon in a day

we understand that:

n= 396 dozen

unit conversion

1 dozen = 12

so

n = 396 dozen gallon

n = 396× 12

n = 4752 gallons

hence 4752 gallons milk is delivered daily

6 0
2 years ago
Apply Crammer's Rule to find the solution to the following quations .2x + 3y = 1, 3x + y = 5​
Bond [772]

Answer:

The solution to the equation system given is:

  • <u>x = 2</u>
  • <u>y = -1</u>

Step-by-step explanation:

First, we must know the equations given:

  1. 2x + 3y = 1
  2. 3x + y = 5​

Following Crammer's Rule, we have the matrix form:

\left[\begin{array}{ccc}2&3\\3&1\end{array}\right] =\left[\begin{array}{ccc}x\\y\end{array}\right] = \left[\begin{array}{ccc}1\\5\end{array}\right]

Now we solve using the determinants:

x=\frac{\left[\begin{array}{ccc}1&3\\5&1\end{array}\right]}{\left[\begin{array}{ccc}2&3\\3&1\end{array}\right] } =\frac{(1*1)-(5*3)}{(2*1)-(3*3)} = \frac{1-15}{2-9} =\frac{-14}{-7} = 2

y=\frac{\left[\begin{array}{ccc}2&1\\3&5\end{array}\right]}{\left[\begin{array}{ccc}2&3\\3&1\end{array}\right] } =\frac{(2*5)-(3*1)}{(2*1)-(3*3)}=\frac{10-3}{2-9} =\frac{7}{-7}=-1

Now, we can find the answer which is x= 2 and y= -1, we can replace these values in the equation to confirm the results are right, with the first equation:

  • 2x + 3y = 1
  • 2(2) + 3(-1)= 1
  • 4 - 3 = 1
  • 1 = 1

And, with the second equation:

  • 3x + y = 5​
  • 3(2) + (-1) = 5
  • 6 - 1 = 5
  • 5 = 5

 

4 0
2 years ago
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