2x+3y=60 solve for x...
x=(60-3y)/2
p=xy^3, using x from above:
p=y^3(60-3y)/2
p=(60y^3-3y^4)/2
dp/dy=(180y^2-12y^3)/2
dp/dy=90y^2-6y^2
dp/dy=0 when:
90y^2-6y^3=0
6y^2(15-y)=0, we know y>0 so
y=15, since x=(60-3y)/2
x=7.5
(We solved it this way because otherwise you get quartic equations and cubic derivatives, yuck :P)
no i think because theres a negative
Answer:
Option B , C , E are characteristics of the function .
Step-by-step explanation:
Given : function f(x)=2(x-4)^5.
To find : What are the characteristics of the function .
Solution : We have given that f(x)=2
.
By the End Point behavior : if the degree is even and leading coefficient is odd of polynomial of function then left end of graph goes down and right goes up.
Since , Option E is correct.
It has degree 5 therefore, function has 5 zeros and atmost 4 maximua or minimum.
Option C is also correct.
By transformation rule it is vertical stretch and shift to right (B )
Therefore, Option B , C , E are characteristics of the function .
Answer:
There is a 55% chance that it won't rain.