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The parabola will show the vertex in the format: y-k = (x-h)^2, where the vertex point
lies at (h, k).
let's first put it in "y =" standard format:
Since we cannot get a perfect square out of this, we complete the square: a=1, b=2, c=3
(b/2)^2 = (2/2)^2 = 1, so
So there's +2 leftover, since 3-1=2; so:
Now we'll subtract the 2 from both sides to show our vertex:
where our vertex (h, k) is at (-1, 2)
lies at (h, k).
let's first put it in "y =" standard format:
Since we cannot get a perfect square out of this, we complete the square: a=1, b=2, c=3
(b/2)^2 = (2/2)^2 = 1, so
So there's +2 leftover, since 3-1=2; so:
Now we'll subtract the 2 from both sides to show our vertex:
where our vertex (h, k) is at (-1, 2)
The discriminant explains how many solutions the quadratic function has. It is found using this formula:
Using the formula, there are three rules. Let's say the discriminant=d:
d<0 - No solution ø
d=0 -ONLY 1 solution
d>0 -2 solutions
In the following graph, there are no solutions as the graph does not hit the x-axis at any point. Thereafter, the discriminant MUST be less than zero. Let's view the options check which one agrees with our answer.
A - Discriminant is greater than 0, which means two solutions. This is WRONG.
B - Discriminant is less than 0, which means no solutions. CORRECT!
C- Discriminant is equal to 0, which means one solution. WRONG!
Your answer is B.
Using the formula, there are three rules. Let's say the discriminant=d:
d<0 - No solution ø
d=0 -ONLY 1 solution
d>0 -2 solutions
In the following graph, there are no solutions as the graph does not hit the x-axis at any point. Thereafter, the discriminant MUST be less than zero. Let's view the options check which one agrees with our answer.
A - Discriminant is greater than 0, which means two solutions. This is WRONG.
B - Discriminant is less than 0, which means no solutions. CORRECT!
C- Discriminant is equal to 0, which means one solution. WRONG!
Your answer is B.