Help plsslsls ill do anything

Can anyone help me solve this

Zigmanuir [339]

Answer:

B

Step-by-step explanation:

THIS IS HOW YOU CAN FIND ANY MISSING ANGLE - ALSO SOLVES FOR X IN THIS QUESTION.

So, a traingle is 180 degrees.

A line is also 180 degrees.

We know that the angles that make up the triangle are 46, 90, and a missing angle

We need to find the missing angle to find x

To find the missing angle, we must subtract the known angles by the 180 degrees of the traingle.

So:

180-90

=

90

90-46

=

44

So we know the missing angle is 44 degrees.

Let subtract the missing angle(44 degrees) by the 180 degrees of the line:

180-44

=

136

<u>THIS IS WHAT ANSWERS THE OPTION METHOD THAT GIVES THE ANSWER</u>

So x equals 136. This is the missing angle x.

So, remember, both the line and the traingle are 180 degrees.

They both need to find the missing value, which we know is 44

The rest of both the triangle and line is 136 degrees.

Well, 136 degrees on the triangle is the known 90+46 degrees.

Since this will be the same on the line, we can think of x as:

90+46

This looks like answer 1.

Hope this helps! :)

Read top part so you can understand how to do future problems, and write in comments if you are confused/need more help.

5 0

3 years ago

Suppose 45% of the population has a college degree.

levacccp [35]

Using the normal distribution, there is a 0.2076 = 20.76% probability that the proportion of persons with a college degree will differ from the population proportion by greater than 3%.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean $\mu$ and standard deviation $\sigma$ is given by:

$Z = \frac{X - \mu}{\sigma}$

The z-score measures how many standard deviations the measure is above or below the mean.

Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

By the Central Limit Theorem, for a proportion p in a sample of size n, the sampling distribution of sample proportion is approximately normal with mean $\mu = p$ and standard deviation $s = \sqrt{\frac{p(1 - p)}{n}}$ , as long as $np \geq 10$ and $n(1 - p) \geq 10$ .

The proportion estimate and the sample size are given as follows:

p = 0.45, n = 437.

Hence the mean and the standard error are:

$\mu = p = 0.45$

$s = \sqrt{\frac{p(1 - p)}{n}} = \sqrt{\frac{0.45(0.55)}{437}} = 0.0238$

The probability that the proportion of persons with a college degree will differ from the population proportion by greater than 3% is <u>2 multiplied by the p-value of Z when X = 0.45 - 0.03 = 0.42</u>.

Hence:

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem:

$Z = \frac{X - \mu}{s}$