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garri49 [273]
3 years ago
13

Find the y-intercept of the following equation: y = 7/2x - 10/7

Mathematics
1 answer:
mote1985 [20]3 years ago
8 0

-10/7 is the answer

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heyy soo i just started math class and im veryy confused I've tried different things to get to the answer but it didn't work soo
german

yes sure, i learned this before so

1. a. make a proportion here, of percentage. \frac{225}{250} =\frac{x}{100} if you cross multiply and divide you get 90%.

1. b. obviously the empty seats would be 10%.

2. a. proportion again, \frac{0.90}{6.00} =\frac{x}{100} cross multiply then divide you ge 15%

3. 30% in decimal form is 0.3. multiply it then to the total amount, so 0.3 x 15 = 4.5

7 0
4 years ago
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A group of 11 students participated in a quiz competition. Their scores are shown below:
GrogVix [38]

Answer:

the other person is right

Step-by-step explanation:

8 0
3 years ago
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Ryan has some nickels and dimes. altogether, he has 34 coins that total $2.60. write and solve a system of equations to determin
777dan777 [17]
N+d=34
.05n+.10d=2.60

Solve by substitution
n=34-d
.05(34-d)+.10d=2.60
1.7-.05d+.10d=2.60
.05d=.90
d=18 dimes
18+n=34
n=16 nickles

4 0
3 years ago
working together, shawn and hector can install a tile floor in 6 hours. it would take shawn 9 hours to do the job alone. what is
Vikki [24]
First, let x be the number of hours it will take for Hector to finish the same job alone. This means that every hour, Hector can do 1/x of the job. The amount of work done by Shawn and Hector in 6 hours should be equal to 1 complete work. This can be expressed as,
                      (1/9 + 1/x)(6) = 1
The value of x is 18. Thus, Hector can to 1/18 of the job in one hour. 
8 0
4 years ago
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Existen tres órdenes de producción en proceso. Las ordenes A y B juntas tienen 150 unidades; B y C juntas, 100 unidades, y A y
Oksanka [162]
Orders are a, b, c, lets write equations to represent the problem's info:
a + b = 150
b + c = 100
a + c = 150
so we have 3 unknowns and 3 equations, so we can solve.
<span>Use the first equation:
a + b = 150
</span>a = 150 - b
and substitute in the 3rd:
<span>a + c = 150
</span>150 - b + c = 150
then
b = c
and we can substitute that in the original equation:
<span>b + c = 100
</span>2b = 100
b = 50
c = 50
and substitute in the first equation:
<span>a + b = 150
</span>a = 150 - b = 150 - 50
a = 100
then a = 100, b = c = 50
3 0
3 years ago
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