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Bas_tet [7]
2 years ago
10

Explain any five applications of computer modeling in beams.

Engineering
1 answer:
coldgirl [10]2 years ago
7 0

Answer:

Explain any five applications of computer modeling in beams.

Explanation:

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What are the nominal dimensions for a 1x2 stick of lumber, a 2x4 stick of lumber and a standard sheet of plywood?
zlopas [31]
3/4 x 1 1/2 inches (19 x 38 mm) is the actual size for 1x2 stick of lumber,

1 1/2 x 3 1/2 inches (38 x 89 mm) is the actually size for a 2x4 stick of lumber,

Plywood is usually sold in 4 x 8-foot sheets. The most common nominal thicknesses of plywood are 1/2 inch and 3/4 inch, but once again the actual sizes are slightly different. A sheet of 1/2-inch plywood is really 15/32 inch thick, while a 3/4-inch sheet is 23/32 inch thick.

Hopefully this answers your question, I apologize if it doesn’t :)
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Consider a fully-clamped circular diaphragm poly-Si with a radius of 250 μm and a thickness of 4 μm. Assume that Young’s modulus
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Explanation:

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A system consists of N very weakly interacting particles at a temperature T sufficiently high so that classical statistical mech
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Risks in driving never begins with yourself, but with other drivers who take risks.
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A large particle composite consisting of tungsten particles within a copper matrix is to be prepared. If the volume fractions of
OverLord2011 [107]

Answer:

Upper bounds 22.07 GPa

Lower bounds 17.59 GPa

Explanation:

Calculation to estimate the upper and lower bounds of the modulus of this composite.

First step is to calculate the maximum modulus for the combined material using this formula

Modulus of Elasticity for mixture

E= EcuVcu+EwVw

Let pug in the formula

E =( 110 x 0.40)+ (407 x 0.60)

E=44+244.2 GPa

E=288.2GPa

Second step is to calculate the combined specific gravity using this formula

p= pcuVcu+pwTw

Let plug in the formula

p = (19.3 x 0.40) + (8.9 x 0.60)

p=7.72+5.34

p=13.06

Now let calculate the UPPER BOUNDS and the LOWER BOUNDS of the Specific stiffness

UPPER BOUNDS

Using this formula

Upper bounds=E/p

Let plug in the formula

Upper bounds=288.2/13.06

Upper bounds=22.07 GPa

LOWER BOUNDS

Using this formula

Lower bounds=EcuVcu/pcu+EwVw/pw

Let plug in the formula

Lower bounds =( 110 x 0.40)/8.9+ (407 x 0.60)/19.3

Lower bounds=(44/8.9)+(244.2/19.3)

Lower bounds=4.94+12.65

Lower bounds=17.59 GPa

Therefore the Estimated upper and lower bounds of the modulus of this composite will be:

Upper bounds 22.07 GPa

Lower bounds 17.59 GPa

7 0
2 years ago
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