11. Technician A says that gasoline storage containers should be painted red. Technician B says that any metal container may be
used for gasoline storage. Who is correct? Name only Both A and B nor B
OTHER QUESTIONS LOOK AT PIC ABOVE PLS ANSWER ALL 
OTHER QUESTIONS LOOK AT PIC ABOVE PLS ANSWER ALL
1 answer:
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Answer:
The complete answer along with step by step explanation and output results is provided below.
Explanation:
Task a)
#include<iostream>
using namespace std;
int main()
{
int op;
double num1, num2;
cout<<"Enter num1 and num2"<<endl;
cin>>num1>>num2;
// To provide the option of required 5 cases
cout << "Select the operation:"
"\n1 = Addition"
"\n2 = Subtraction"
"\n3 = Multiplication"
"\n4 = Division"
"\n5 = Negation\n";
cin >> op; // user input the desired operation
switch(op) // switch to the corresponding case according to user input
{
case 1:
cout <<"The Addition of num1="<<num1<<" and num2="<<num2<<" is: "<<num1+num2;
break;
case 2:
cout <<"The Subtraction of num1="<<num1<<" and num2="<<num2<<" is: "<<num1-num2;
break;
case 3:
cout <<"The Multiplication of num1="<<num1<<" and num2="<<num2<<" is: "<<num1*num2;
break;
case 4:
while(num2 == 0) // to check if divisor is zero
{
cout << "\nWrong divisor! Please select the correct divisor again: ";
cin >> num2; // if divisor is zero then ask user to input num2 again
}
cout <<"The division of num1="<<num1<<" and num2="<<num2<<" is: "<<num1/num2;
break;
case 5:
cout <<"The Negation of num1="<<num1<<" and num2="<<num2<<" is: "<<-1*num1<<" "<<-1*num2;
break;
default:
// If the operation is other than listed above then error will be shown
cout << "Error! The selected operatorion is not correct";
break;
}
return 0;
}
Output:
Test 1:
Enter num1 and num2
2
9
Select the operation:
1 = Addition
2 = Subtraction
3 = Multiplication
4 = Division
5 = Negation
1
The Addition of num1=2 and num2=9 is: 11
Hence the output is correct and working as it was required
Test 2:
Enter num1 and num2
8
0
Select the operation:
1 = Addition
2 = Subtraction
3 = Multiplication
4 = Division
5 = Negation
4
Wrong divisor! Please select the correct divisor again: 2
The Division of num1=8 and num2=2 is: 4
Hence the output is correct and working as it was required
Test 3:
Enter num1 and num2
-2
4
Select the operation:
1 = Addition
2 = Subtraction
3 = Multiplication
4 = Division
5 = Negation
5
The Negation of num1=-2 and num2=4 is: 2 -4
Hence the output is correct and working as it was required
Task b)
#include<iostream>
#include<cmath> // required to calculate square root
using namespace std;
int main()
{
int op;
double num;
cout<<"Enter a real number > 0"<<endl;
cin>>num;
cout << "Press 1 for square root:";
cin >> op;
switch(op) // switch to the corresponding case according to user input
{
case 1:
if (num <= 0) // to check if number is less or equal to zero
{
cout << "\nError! number is not valid";
break; // if number is not valid then terminate program
}
cout <<"The square root of num="<<num<<" is: "<<sqrt(num);
// if number is valid then square root will be calculated
break;
default:
// If the operation is other than listed above then error will be shown
cout << "Error! The selected operation is not correct";
break;
}
return 0;
}
Output:
Test 1:
Enter a real number > 0
6
Press 1 for square root: 1
The square root of num=6 is: 2.44949
Hence the output is correct and working as it was required
Test 2:
Enter a real number > 0
-4
Press 1 for square root: 1
Error! number is not valid
Hence the output is correct and working as it was required
Answer:
a. 0.11
b. 110 students
c. 50 students
d. 0.46
e. 460 students
f. 540 students
g. 0.96
Explanation:
(See attachment below)
a. Probability that a student got an A
To get an A, the student needs to get 9 or 10 questions right.
That means we want P(X≥9);
P(X>9) = P(9)+P(10)
= 0.06+0.05=0.11
b. How many students got an A on the quiz
Total students = 1000
Probability of getting A = 0.11 ---- Calculated from (a)
Number of students = 0.11 * 1000
Number of students = 110 students
So,the number of students that got A is 110
c. How many students did not miss a single question
For a student not to miss a single question, then that student scores a total of 10 out of possible 10
P(10) = 0.05
Total Students = 1000
Number of Students = 0.05 * 1000
Number of Students = 50 students
We see that 5
d. Probability that a student pass the quiz
To pass, a student needed to get at least 6 questions right.
So we want P(X>=6);
P(X>=) =P(6)+P(7)+P(8)+P(9)+P(10)
=0.08+0.12+0.15+0.06+0.05=0.46
So, the probability of a student passing the quiz is 0.46
e. Number of students that pass the quiz
Total students = 1000
Probability of passing the quiz = 0.46 ----- Calculated from (d)
Number of students = 0.46 * 1000
Number of students = 460 students
So,the number of students that passed the test is 460
f. Number of students that failed the quiz
Total students = 1000
Total students that passed = 460 ----- Calculated from (e)
Number of students that failed = 1000 - 460
Number of students that failed = 540
So,the number of students that failed is 540
g. Probability that a student got at least one question right
This means that we want to solve for P(X>=1)
Using the complement rule,
P(X>=1) = 1 - P(X<1)
P(X>=1) = 1 - P(X=0)
P(X>=1) = 1 - 0.04
P(X>=1) = 0.96
