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MissTica
3 years ago
7

11. Technician A says that gasoline storage containers should be painted red. Technician B says that any metal container may be

used for gasoline storage. Who is correct? Name only Both A and B nor B
OTHER QUESTIONS LOOK AT PIC ABOVE PLS ANSWER ALL ​

Engineering
1 answer:
QveST [7]3 years ago
6 0

Explanation:

1. Both a and b only

2. A only

3. B only

4.Neither a or b

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When moving cylinders always remove and make
Karolina [17]

Unless cylinders are firmly secured on a special carrier intended for this purpose, regulators shall be removed and valve protection caps put in place before cylinders are moved. A suitable cylinder truck, chain, or other steadying device shall be used to keep cylinders from being knocked over while in use.

5 0
3 years ago
He is going ___ in the hot air ballon​
Vladimir [108]

no artical shoul be used here

5 0
2 years ago
Before cutting coarse screw threads, the operator should lubricate: A. The leadscrew and gearbox B. The ways and cross slide C.
Maksim231197 [3]

Answer:

(d) all of the above

Explanation:

before cutting the screw threads the operator should lubricate all of the machine parts given in the option that is lead screw and gearbox , the ways and the cross slide and the carriage and half-nuts. we should use lubrication because it reduces the overall system friction and if friction is reduced then heat generated due to friction is also decreases which is beneficial

so option (D) will be correct because we need lubricate in all the given parts  

8 0
3 years ago
A spring-mass-damper instrument is employed for acceleration measurements. The spring constant is 12000 N/m. The mass is 5 g. Th
shepuryov [24]

Answer:

a) 246.56 Hz

b) 203.313 Hz

c) Add more springs

Explanation:

Spring constant = 12000 N/m

mass = 5g = 5 * 10^-3 kg

damping ratio = 0.4

<u>a) Calculate Natural frequency </u>

Wn = √k/m = \sqrt{12000 /  5*10^{-3}  }

                   = 1549.19 rad/s  ≈ 246.56 Hz

<u>b) Bandwidth of instrument </u>

W / Wn = \sqrt{1-2(0.4)^2}

W / Wn = 0.8246

therefore Bandwidth ( W ) = Wn * 0.8246 = 246.56 * 0.8246 = 203.313 Hz

C ) To increase the bandwidth we have to add more springs

5 0
3 years ago
Technician A says that excessive end play causes rapid wear of the sealing rings and possibly the sealing ring groove. Technicia
DerKrebs [107]

Answer:

Technician A only

Explanation:

Rapid wear of the sealing ring and the seal ring groove are result of excessive end play

7 0
3 years ago
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