I think it is the second one but I’m not for sure I’m really just doing this for points
The solution to the inequality is -20.8 > p (imagine the symbol is the symbol for at least)
Answer:
The inverse for log₂(x) + 2 is - log₂x + 2.
Step-by-step explanation:
Given that
f(x) = log₂(x) + 2
Now to find the inverse of any function we put we replace x by 1/x.
f(x) = log₂(x) + 2
f(1/x) =g(x)= log₂(1/x) + 2
As we know that
log₂(a/b) = log₂a - log₂b
g(x) = log₂1 - log₂x + 2
We know that log₂1 = 0
g(x) = 0 - log₂x + 2
g(x) = - log₂x + 2
So the inverse for log₂(x) + 2 is - log₂x + 2.
Answer:
The answer is D
Step-by-step explanation:
Plug any x value for the y values of f(x) and g(x)
Let's do 0 since it is easier.
f(x)=-2(0)-4=-4
g(x)=-2(0)+2=2
So, g(x) is 6 greater than f(x).
Thus, g is most likely moved 6 units up from f.
Graph the 2 functions on Desmos for a better picture.
Answer:
the ans is
Step-by-step explanation:
V=πr2h=π·32·6≈169.646
