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Dafna11 [192]
3 years ago
11

Which digit in 123.456 has highest value? Digit 6 5 4 1

Mathematics
2 answers:
Vlad [161]3 years ago
8 0

Answer:

1

Step-by-step explanation:

The 1 is in the hundredth's place and it has the highest value

Lubov Fominskaja [6]3 years ago
3 0

<em>Which digit in 123.456 has highest value?</em>

<em>answer</em><em> </em><em>=</em><em> </em><em>1</em><em>.</em><em>.</em><em>.</em><em>.</em>

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There are 11 more goats than sheep in the farm. Together there are 137 animals in the farm. How many goats and how many sheep ar
VashaNatasha [74]

Answer:

The number of goats in the farm is 74

The number of sheep in the farm is 63

Step-by-step explanation:

Let

x----> the number of goats in the farm

y----> the number of sheep    

we know that

x+y=137 ----> equation A

x=y+11 -----> equation B

substitute the equation B in equation A and solve for y

(y+11)+y=137

2y=137-11

2y=126

y=126/2=63

Find the value of x

x=63+11=74

therefore

The number of goats in the farm is 74

The number of sheep in the farm is 63

8 0
3 years ago
Q1 A ball is thrown upwards with some initial speed. It goes up to a height of 19.6m and then returns. Find (a) The initial spee
lubasha [3.4K]

Answer:

(a)  19.6 ms⁻¹

(b)  2 s

(c)  9.8 ms⁻¹

(d)  4 s

Step-by-step explanation:

<u>Constant Acceleration Equations (SUVAT)</u>

\boxed{\begin{array}{c}\begin{aligned}v&=u+at\\\\s&=ut+\dfrac{1}{2}at^2\\\\ s&=\left(\dfrac{u+v}{2}\right)t\\\\v^2&=u^2+2as\\\\s&=vt-\dfrac{1}{2}at^2\end{aligned}\end{array}} \quad \boxed{\begin{minipage}{4.6 cm}$s$ = displacement in m\\\\$u$ = initial velocity in ms$^{-1}$\\\\$v$ = final velocity in ms$^{-1}$\\\\$a$ = acceleration in ms$^{-2}$\\\\$t$ = time in s (seconds)\end{minipage}}

When using SUVAT, assume the object is modeled as a particle and that acceleration is constant.

Acceleration due to gravity = 9.8 ms⁻².

<h3><u>Part (a)</u></h3>

When the ball reaches its maximum height, its velocity will momentarily be zero.

<u>Given values</u> (taking up as positive):

s=19.6 \quad v=0 \quad a=-9.8

\begin{aligned}\textsf{Using} \quad v^2&=u^2+2as\\\\\textsf{Substitute the given values:}\\0^2&=u^2+2(-9.8)(19.6)\\0&=u^2-384.16\\u^2&=384.16\\u&=\sqrt{384.16}\\\implies u&=19.6\; \sf ms^{-1}\end{aligned}

Therefore, the initial speed is 19.6 ms⁻¹.

<h3><u>Part (b)</u></h3>

Using the same values as for part (a):

\begin{aligned}\textsf{Using} \quad s&=vt-\dfrac{1}{2}at^2\\\\\textsf{Substitute the given values:}\\19.6&=0(t)-\dfrac{1}{2}(-9.8)t^2\\19.6&=4.9t^2\\t^2&=\dfrac{19.6}{4.9}\\t^2&=4\\t&=\sqrt{4}\\\implies t&=2\; \sf s\end{aligned}

Therefore, the time taken to reach the highest point is 2 seconds.

<h3><u>Part (c)</u></h3>

As the ball reaches its maximum height at 2 seconds, one second before this time is 1 s.

<u>Given values</u> (taking up as positive):

u=19.6 \quad a=-9.8 \quad t=1

\begin{aligned}\textsf{Using} \quad v&=u+at\\\\\textsf{Substitute the given values:}\\v&=19.6+(-9.8)(1)\\v&=19.6-9.8\\\implies v&=9.8\; \sf ms^{-1}\end{aligned}

The velocity of the ball one second before it reaches its maximum height is the <u>same</u> as the velocity one second after.

<u>Proof</u>

When the ball reaches its maximum height, its velocity is zero.

Therefore, the values for the downwards journey (from when it reaches its maximum height):

u=0 \quad a=9.8 \quad t=1

(acceleration is now positive as we are taking ↓ as positive).

\begin{aligned}\textsf{Using} \quad v&=u+at\\\\\textsf{Substitute the given values:}\\v&=0+9.8(1)\\\implies v&=9.8\; \sf ms^{-1}\end{aligned}

Therefore, the velocity of the ball one second before <u>and</u> one second after it reaches the maximum height is 9.8 ms⁻¹.

<h3><u>Part (d)</u></h3>

From part (a) we know that the time taken to reach the highest point is 2 seconds.  Therefore, the time taken by the ball to travel from the highest point to its original position will also be 2 seconds.

Therefore, the total time taken by the ball to return to its original position after it is thrown upwards is 4 seconds.

4 0
1 year ago
Rectangle ABCD is graphed in the coordinate plane. The following are the vertices of the rectangle: A(3,-2), B(6,-2), C(6,5) and
rosijanka [135]

The area of ABCD is 21

8 0
3 years ago
A marketing researcher must determine how many telephone numbers she needs to order from a sample provider to complete a survey
vfiekz [6]

Answer:

the required number of telephone orders to complete the 400 interviews is 3433

Step-by-step explanation:

Given the data in the question;

Let us represent the telephone numbers the researcher orders to complete the 400 interviews with Y.

Thus, The working phone numbers = 70% × Y

Now, number of ATM users = 45% × The working ph0ne numbers

⇒ 45% × ( 70% × Y )

number of ATM users = 0.45 × 0.70 × Y = 0.315Y

Thus; Number of people contacted that agrees to complete the survey will be;

⇒ 37% × number of ATM users

⇒ 0.37 × 0.315Y = 0.11655Y

so, since the researcher needs at least 400 interviews

Hence;

0.11655Y ≥ 400

Y ≥ 400 / 0.11655

Y ≥ 3432.0034 ≈ 3433

Therefore, the required number of telephone orders to complete the 400 interviews is 3433

5 0
3 years ago
CAN YOU PLSSSSSSSSSSSSSSSSSSS HELP ME WITH THIS
Bond [772]

Answer:

I think its b

Step-by-step explanation:

4 0
3 years ago
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