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Misha Larkins [42]
3 years ago
14

Which graph is the solution of the following systems HELP ON ON GRADPOINT

Mathematics
1 answer:
makkiz [27]3 years ago
6 0
I think it is the second one but I’m not for sure I’m really just doing this for points
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Greg has a bag that contains 25 colored tiles. Of all the tiles in this​ bag, 10 are blue. Suppose another bag contains 250 colo
Sergio [31]

Answer:

he is less likely to pick a blue tile in the second bag

Step-by-step explanation:

divide 10 by 25 which will give you 40%

divide 75 by 250 which will give you 30%

this makes it less likely for Greg to pick blue from the second bag, as the first bag has a higher percentage chance

6 0
3 years ago
Profit is the amount of money that remains after all expenses of a project have been paid. The year has just​ ended, and Ajax​ C
lilavasa [31]

Answer:

the Profit earned by the company is $280,489

Step-by-step explanation:

Total Cost of 5 projects awarded = $7,435,000

Cost of Project​ 1 = $1,245,000

Cost of Project​ 2 = $985,689

Cost of  Project​ 3 = $1,723,000

Cost of Project​ 4 = $2,567,054

Cost of Project​ 5 = $633,768

We need to find the profit earned by the company.

First we need to find Total cost spent on all 5 projects.

It can be found by adding cost spent on all projects.

Total cost spent on all 5 projects = Cost of Project 1 + Cost of Project 2 + Cost of Project 3 + Cost of Project 4 + Cost of Project 5

Total cost spent on all 5 projects = $1,245,000+ $985,689 + $1,723,000+ $2,567,054 + $633,768

Total cost spent on all 5 projects = $7,154,511

Now we can calculate profit earned using formula:

Profit earned = Total Cost of 5 projects awarded - Total cost spent on all 5 projects

Profit earned = $7,435,000 - $7,154,511

Profit earned = $1,280,489

So, the Profit earned by the company is $280,489

6 0
3 years ago
Which is the product of 4^4(4^-7)(4)?
Degger [83]

Answer:

1/16 or 0.0625

Step-by-step explanation:

we can take 4 outside the parentheses and we would get 4^(4-7+1)=4^(-2)= 1/(4^2)=1/16=0.0625.

3 0
3 years ago
Read 2 more answers
Please help, very hard question (for me), Will give Brainliest!!!
AleksAgata [21]
The answer is D. This is because when you take 10.65 and subtract 9.95 from it you get 0.07. If you take this number and continuously add to 9.95 you get the numbers provided in the chart. We'll also notice that the 0.07 is only added after 10 minutes of talking (10,20,30,etc.).
8 0
4 years ago
Field book of an land is given in the figure. It is divided into 4 plots . Plot I is a right triangle , plot II is an equilatera
Kazeer [188]

Answer:

Total area = 237.09 cm²

Step-by-step explanation:

Given question is incomplete; here is the complete question.

Field book of an agricultural land is given in the figure. It is divided into 4 plots. Plot I is a right triangle, plot II is an equilateral triangle, plot III is a rectangle and plot IV is a trapezium, Find the area of each plot and the total area of the field. ( use √3 =1.73)

From the figure attached,

Area of the right triangle I = \frac{1}{2}(\text{Base})\times (\text{Height})

Area of ΔADC = \frac{1}{2}(\text{CD})(\text{AD})

                        = \frac{1}{2}(\sqrt{(AC)^2-(AD)^2})(\text{AD})

                        = \frac{1}{2}(\sqrt{(13)^2-(19-7)^2} )(19-7)

                        = \frac{1}{2}(\sqrt{169-144})(12)

                        = \frac{1}{2}(5)(12)

                        = 30 cm²

Area of equilateral triangle II = \frac{\sqrt{3} }{4}(\text{Side})^2

Area of equilateral triangle II = \frac{\sqrt{3}}{4}(13)^2

                                                = \frac{(1.73)(169)}{4}

                                                = 73.0925

                                                ≈ 73.09 cm²

Area of rectangle III = Length × width

                                 = CF × CD

                                 = 7 × 5

                                 = 35 cm²

Area of trapezium EFGH = \frac{1}{2}(\text{EF}+\text{GH})(\text{FJ})

Since, GH = GJ + JK + KH

17 = \sqrt{9^{2}-x^{2}}+5+\sqrt{(15)^2-x^{2}}

12 = \sqrt{81-x^2}+\sqrt{225-x^2}

144 = (81 - x²) + (225 - x²) + 2\sqrt{(81-x^2)(225-x^2)}

144 - 306 = -2x² + 2\sqrt{(81-x^2)(225-x^2)}

-81 = -x² + \sqrt{(81-x^2)(225-x^2)}

(x² - 81)² = (81 - x²)(225 - x²)

x⁴ + 6561 - 162x² = 18225 - 306x² + x⁴

144x² - 11664 = 0

x² = 81

x = 9 cm

Now area of plot IV = \frac{1}{2}(5+17)(9)

                                = 99 cm²

Total Area of the land = 30 + 73.09 + 35 + 99

                                    = 237.09 cm²

7 0
3 years ago
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