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Alex Ar [27]
3 years ago
13

Mr. Starnes and his wife have 6 grandchildren: Connor, Declan, Lucas, Piper, Sedona, and Zayne. They have 2 extra tickets to a h

oliday show, and will randomly select which 2 grandkids get to see the show with them. Find the probability that at least one of the girls (Piper and Sedona) get to go to the show.
Mathematics
1 answer:
tiny-mole [99]3 years ago
8 0

Answer:

the probability that at least one of the girls (Piper and Sedona) get to go to the show is 0.533

Step-by-step explanation:

The computation of the probability that have at least one of the girl get to go is shown below;

= \frac{^2C_1 \times ^4C_1}{^6C_2} \\\\= \frac{8}{15}\\\\= 0.53333

Hence, the probability that at least one of the girls (Piper and Sedona) get to go to the show is 0.533

So the same is relevant

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Alexis buys groceries using her credit card her card has an APR of 19.99% and she must pay at least 5% of the balance at the end
avanturin [10]

Answer:

The answer is that she would pay $65.56 in finance charges at the end of the month.

Step-by-step explanation:

Given: APR = 19.99%

Carry Over Balance: $398.97

The APR or Annual Percentage Rate, is calculated daily. You will need to get the daily periodic rate, or DPR, so divide the APR by 365:

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To get the finance charge, multiply the average daily balance by the DPR and then by 30 days:

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mars1129 [50]

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Step-by-step explanation:

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Calculate the annual return percentage
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The annual returns will be calculated as follows:
a] Here we use the formula:
A=p(1+r/100)^n
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p=principle
r=returns
n=time
We are given:
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Plugging the values in the formula we obtain:
500=400(1+r)^1
simplifying and solving for r:
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b] Using the formula above:
A=p(1+r/100)^n
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plugging the values in the equation we obtain:
2600=2000(1+r)^1
simplifying and solving for r we obtain:
2600/2000=1+r
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