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Tpy6a [65]
2 years ago
14

Helpppppp pleaseeeeeeeeeeee

Mathematics
2 answers:
Nesterboy [21]2 years ago
4 0
Ya is shebought 6 errs seeds sk
Lyrx [107]2 years ago
3 0

Answer:

She bought 6 erasers.

Step-by-step explanation:

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The radii of Earth and Pluto are 6,371 kilometers and 1,161 kilometers, respectively.
abruzzese [7]

Answer:

A

Step-by-step explanation:

5 0
2 years ago
When solving a linear inequality, what is different compared to solving a linear equa- tion? For which steps do you have to hbe
elena55 [62]

Answer:

See explanation below

Step-by-step explanation:

When solving a linear inequality, the main difference resides in the following:

When we change the signs of the terms (either from positive to negative or from negative to positive) we have to change the sign of the inequality (if the sign was ≥, we change it to ≤, if the sign was ≤, we change it to ≥). Therefore we have to be more careful while doing this.

6 0
2 years ago
Need help with this ASAP​
gizmo_the_mogwai [7]

Given:

(3x-2)^9

To find:

The coefficient of x^6 in the expansion of (3x-2)^9.

Solution:

We know that, in the expansion of (x+y)^n,

T_{r+1}=^nC_rx^{n-r}y^r       ...(i)

(3x-2)^9 has only one x and in x^6, the power of x is 6. It is possible if

n-r=6

9-r=6

9-6=r

3=r

Putting n=9, r=3, x=3x and y=-2 in (i), we get

T_{3+1}=^9C_3(3x)^{9-3}(-2)^3

T_{4}=\dfrac{9!}{3!(9-3)!}\times (3x)^{6}(-8)

T_{4}=\dfrac{9\times 8\times 7\times 6!}{3\times 2\times 1\times (9-3)!}\times (729x^{6})(-8)

T_{4}=84\times (729)\times (-8)\times x^{6}

T_{4}=-489888x^6

Therefore, the coefficient of x^6 in the expansion of (3x-2)^9 is -489888.

5 0
2 years ago
I have 10 minutes, Help! Joani has some stuffed animals. She has 2 times as many as Lily. Lily has 6 stuffed animals. Joanie gav
tangare [24]
The answer is:  (6x2) - 2= 10 +4=14

6 0
2 years ago
Read 2 more answers
Three hundred AU $ would have exchanged to how many Yen?
RSB [31]

Answer:

23911.63

Step-by-step explanation:

1aud=79.71 yen, so 300 would be 79.71*300

can i have brainlist? i need one more to rank up. thanks

4 0
2 years ago
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