Please help me I have no idea what this is

Marina86 [1]

$Greatest\ common\ factor\ is\ the\ highest\ number\ by\ witch\ 45, \ 51\ and\\ 63\ can\ be\ divided\\\\
45:3\\
15:3\\
5:5\\\\
51:3\\
17:17\\\\63:3\\21:3\\7:7\\\\GCF=3\\\\Greatest\ common\ factor\ of\ 45,\ 63\ and\ 51\ is\ equal\ to\ 3.
$

7 0

3 years ago

Use the formula an = d (n − 1) + aj to write a formula for the arithmetic sequence below.

xenn [34]

Answer:

$a_{n}$ = 4n - 2

Step-by-step explanation:

There is a common difference d between consecutive terms in the sequence, that is

6 - 2 = 10 - 6 = 14 - 10 = 18 - 14 = 4

This indicates the sequence is arithmetic with n th term

$a_{n}$ = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Here a₁ = 2 and d = 4 , thus

$a_{n}$ = 2 + 4(n - 1) = 2 + 4n - 4 = 4n - 2

3 0

2 years ago

Find the value of the cosine for ZA.

baherus [9]

Answer:

C. $\frac{8\sqrt{89}}{89}$

Step-by-step explanation:

Cos A = Adj/Hyp

Reference angle = <A

Adjacent side = 8 ft

Hypotenuse = √(8² + 5²) = √89 (pythagorean theorem)

Thus:

$Cos (A) = \frac{8}{\sqrt{89}}$

Rationalize

$Cos (A) = \frac{8 * \sqrt{89}}{\sqrt{89} * \sqrt{89}}$

$Cos (A) = \frac{8\sqrt{89}}{89}$

5 0

2 years ago

A lay came to the market to sell eggs . We first customer bought 1/2 of all her eggs and 1/2 of an egg. Her second customer boug

Bezzdna [24]

Given:

First customer bought 1/2 of all eggs of lady seller and 1/2 of an egg.

Her second customer bought 1/2 of all the remaining eggs and 1/2 of an egg.

At this point she had sold all her eggs.

To find:

The number of egg the lady have when she came to the market.

Solution:

Let x be the number of egg that the lady have when she came to the market.

First customer bought 1/2 of all eggs of lady seller and 1/2 of an egg. So, the number of remaining eggs after first customer is

$x-\dfrac{1}{2}x-\dfrac{1}{2}=\dfrac{x}{2}-\dfrac{1}{2}$

Her second customer bought 1/2 of all the remaining eggs and 1/2 of an egg. So, the number of remining egg after second customer is

$\text{Remaining eggs}=\dfrac{x}{2}-\dfrac{1}{2}-(\dfrac{x}{2}-\dfrac{1}{2})\times \dfrac{1}{2}-\dfrac{1}{2}$

$=\dfrac{x}{2}-\dfrac{1}{2}-\dfrac{x}{4}+\dfrac{1}{4}-\dfrac{1}{2}$

$=(\dfrac{x}{2}-\dfrac{x}{4})+(-\dfrac{1}{2}+\dfrac{1}{4}-\dfrac{1}{2})$

$=(\dfrac{2x-x}{4})+(\dfrac{-2+1-2}{4})$

$=\dfrac{x}{4}-\dfrac{3}{4}$

At this point she had sold all her eggs. It means the remining eggs is 0.

$\dfrac{x}{4}-\dfrac{3}{4}=0$

$\dfrac{x}{4}=\dfrac{3}{4}$

Multiply both sides by 4.

$x=3$

Therefore, the lady came to the market is with 3 eggs.

8 0

3 years ago

La montaña más alta del mundo es Everest cuya altura es de 8.848m y la altura de la segunda montaña más alta es de 2hm 3dam y 7m

olchik [2.2K]

Answer:

La segunda montaña más alta del mundo tiene 8611 metros.

Step-by-step explanation:

La montaña más alta del mundo es Everest cuya altura es de 8.848m.

La altura de la segunda montaña más alta es de 2hm 3dam y 7m menos. Para calcular la altura que tiene la segunda montaña más alta del mundo, debes realizar primero un cambio de unidades sabiendo que

1 hm= 100 m
1 dam= 10 m

Entonces podes aplicar las siguientes reglas de tres simple:

Si 1 hm equivale a 100 m, 2 hm equivale a ¿Cuántos metros?

$metros=\frac{2 hm*100 m}{1 hm}$

metros= 200

Si 1 dam equivale a 10 m, 3 dam equivale a ¿Cuántos metros?

$metros=\frac{3 dam*10 m}{1 dam}$

metros= 30

Entonces, la altura de la segunda montaña más alta es de 200 m+30 m+ 7 m menos que el Everest. Esto es, 237 metros menos que la montaña más alta del mundo. Entonces:

8848 metros - 237 metros= 8611 metros

<u><em>La segunda montaña más alta del mundo tiene 8611 metros.</em></u>

6 0

3 years ago