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tiny-mole [99]
3 years ago
7

In the reaction, 2HgO(s)⟶2Hg(s) O2(g). How many liters of oxygen, O2 measured at STP, would be produced from the decomposition o

f 111 g of mercury(II) oxide, HgO?
Chemistry
1 answer:
Wittaler [7]3 years ago
5 0

Answer:

5.74 L O₂

General Formulas and Concepts:

<u>Chemistry - Gas Laws</u>

  • Reading a Periodic Table
  • Using Stoichiometry
  • STP (Standard Conditions for Temperature and Pressure) = 22.4 L per mole at 1 atm, 273 K

Explanation:

<u>Step 1: Define</u>

RxN:   2HgO (s) → 2Hg (s) + O₂ (g)

Given:   111 g HgO

<u>Step 2: Identify Conversions</u>

STP

Molar Mass of Hg - 200.59 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of HgO - 200.59 + 16.00 = 216.59 g/mol

<u>Step 3: Stoichiometry</u>

<u />111 \ g \ HgO(\frac{1 \ mol \ HgO}{216.59 \ g \ HgO} )(\frac{1 \ mol \ O_2}{2 \ mol \ HgO} )(\frac{22.4 \ L \ O_2}{1 \ mol \ O_2} ) = 5.73988 L O₂

<u>Step 4: Check</u>

<em>We are given 3 sig figs. Follow sig fig rules and round.</em>

5.73988 L O₂ ≈ 5.74 L O₂

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4. Magnesium and oxygen undergo a chemical reaction to
erastovalidia [21]

Answer:

About 16.1 grams of oxygen gas.

Explanation:

The reaction between magnesium and oxygen can be described by the equation:
\displaystyle 2\text{Mg} + \text{O$_2$} \longrightarrow 2\text{MgO}

24.4 grams of Mg reacted with O₂ to produce 40.5 grams of MgO. We want to determine the mass of O₂ in the chemical change.

Compute using stoichiometry. From the equation, we know that two moles of MgO is produced from every one mole of O₂. Therefore, we can:

  1. Convert grams of MgO to moles of MgO.
  2. Moles of MgO to moles of O₂
  3. And moles of O₂ to grams of O₂.

The molecular weights of MgO and O₂ are 40.31 g/mol and 32.00 g/mol, respectively.

Dimensional analysis:

\displaystyle 40.5\text{ g MgO} \cdot \frac{1\text{ mol MgO}}{40.31\text{ g MgO}} \cdot \frac{1\text{ mol O$_2$}}{2\text{ mol MgO}} \cdot \frac{32.00\text{ g O$_2$}}{1\text{ mol O$_2$}} = 16.1\text{ g O$_2$}

In conclusion, about 16.1 grams of oxygen gas was reacted.

You will obtain the same result if you compute with the 24.4 grams of Mg instead:

\displaystyle 24.4\text{ g Mg}\cdot \frac{1\text{ mol Mg}}{24.31\text{ g Mg}} \cdot \frac{1\text{ mol O$_2$}}{1\text{ mol Mg}} \cdot \frac{32.00\text{ g O$_2$}}{1\text{ mol O$_2$}} = 16.1\text{ g O$_2$}

3 0
2 years ago
What are some possible ways these rocks were formed? Be sure to discuss all 3 rocks.<br> pls help me
horrorfan [7]

The brownish rock is a sedimentry rock was formed when things like sand, mud, or pebbles get laid down in layers. Eventually the layers are lithified.

The grey rock is a metamorphic rock and was when other rocks are changed because of heat or pressure. Earth movements can cause rocks to be deeply buried or squeezed. As a result, the rocks are heated and put under great pressure. They do not melt, but the minerals they contain are changed chemically, forming metamorphic rocks.

The red dots rock is an igneous rock. Igneous rock forms when hot, molten rock crystallizes and solidifies.

8 0
3 years ago
Read 2 more answers
The teal line of the hydrogen emission spectrum has a wavelength of 486.0 nm. A hydrogen emission spectrum has a violet, a blue,
Sloan [31]

Answer:

The correct answer to the following question will be "4.08 × 10⁻¹⁹ Joule".

Explanation:

Given:

Wavelength, λ = 486.0 nm

As we know,

E=h\upsilon =\frac{hc}{\lambda}

On putting the estimated values, we get

⇒          =\frac{1241.5 \ ev\ nm}{486 \ nm}

⇒          =2.554 \ ev

∴ 1 ev = 1.6 × 10⁻¹⁹ J

Now,

Energy, E=2.554\times 1.6\times 10^{-19}

⇒               =4.08\times 10^{-19} Joule

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masya89 [10]
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8 0
4 years ago
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wolverine [178]

This is mind numbing, but I got you.

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