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aivan3 [116]
3 years ago
9

What happens when exhaled air passes through clear lime water?​

Chemistry
1 answer:
dimulka [17.4K]3 years ago
3 0
Huh what type of question is that?!
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Many popular beverages are sold in two-kilo bottles. true or false
Molodets [167]
False. The answer is liter. kilo is the base (liter) times 1000. it would make no sense.
5 0
3 years ago
During which change of state do atoms lose energy
alexgriva [62]

Answer: Atoms lose energy as a gas changes to a solid.

Explanation:

6 0
2 years ago
Read 2 more answers
How do I balance this equation?
gavmur [86]

Answer: place a 2 in front of NaNo3 on left side of equation while leaving the other blanks empty or you can place a 1 in those blanks

Explanation:

Step 1 count and write down the amount of each given element for both sides

Step 2 begin placing numbers (coefficients) to each side to balance

7 0
3 years ago
Determine how many oxygeng atoms are in 5.00 g of sample of sodium dichromate, na2cr2o7
vlada-n [284]

The number of oxygen atoms is in 5.00 g of sample of sodium dichromate, Na₂Cr₂O₇ is 1.125 x 10²³ atoms.

<h3>What is sodium dichromate?</h3>

Sodium dichromate is an inorganic compound. It is sued in tanning and mental illness.

The molar mass of sodium = 23 gm

The molar mass of Cr = 51.99 gm

The molar mass of oxygen = 16 gm

Molar mass of Na₂Cr₂O₇ = 2(23) + 2(51.99) + 7(16) = 261.98 gm

Number of moles in 7 gm = mass / molar mass = 7 / 261.98 = 0.0267 moles

1 mole of  Na₂Cr₂O₇ contains 7 moles of oxygen, therefore:

The number of moles of oxygen in 0.0267 moles = 0.0267 x 7 = 0.1869 moles

Thus, the number of atoms = 0.1869 x 6.02 x 10^23 = 1.125 x 10²³ atoms.

To learn more about sodium dichromate, refer to the link:

brainly.com/question/1444529

#SPJ4

6 0
2 years ago
The solubility of a certain compound in ice-cold water is 0.16 g in 100 mL. Its solubility in hot water is 4.35 g in 100 mL. Wha
jonny [76]

Answer:

96.32 %

Explanation:

Given that:

The solubility of compound in hot water = 4.35 g / 100 mL

The solubility of compound in cold water = 0.16 g / 100 mL

Which means that in 100 mL of hot water, the dissolved compound is 4.35 g and in cold water, the dissolved compound is 0.16 g

Hence, on transition, compound that will catalyze is 4.35 - 0.16 g = 4.19 g

So,

\%=\frac {4.19}{4.35}\times 100

Percent recovery for re-crystallization of this compound from water= 96.32 %

3 0
3 years ago
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