Molar mass :
NH₃ = 17.0 g/mol
(NH₄)₂SO₄ = 132 g/mol
2 NH₃ + H₂SO₄ = (NH₄)₂SO₄
2 x 17 g NH₃ ------------ 132 g <span> (NH</span>₄)₂SO<span>₄
</span>( mass NH₃) ------------ 1.90 x 10⁵ <span> (NH</span>₄)₂SO<span>₄
( mass NH</span>₃) = (1.90 x 10⁵) x 2 x 17 / 132
<span>
( mass NH</span>₃) = 6460000 / 132
<span>
( mass NH</span>₃) = 48939.39 g
<span>
in kg :
48939.39 / 1000 = 48.93 kg = 4.893 x 10</span>¹ kg
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hope this helps!
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</span>
Answer:
beakers and flasks
Explanation:
its better to use accurate measuring instruments for measuring volume
Answer:
The rate is a mathematical relationship obtained by comparing reaction rate with reactant concentrations.
Answer:
Holmium can absorb neutrons, so it is used in nuclear reactors to keep a chain reaction under control. Its alloys are used in some magnets. Holmium has no known biological role, and is non-toxic. Holmium is found as a minor component of the minerals monazite and bastnaesite.
Explanation:
this is basically used in industries
Answer:
11.9 g of nitrogen monoxide
Explanation:
We'll begin by calculating the number of mole in 6.75 g of NH₃. This can be obtained as follow:
Mass of NH₃ = 6.75 g
Molar mass of NH₃ = 14 + (3×1)
= 14 + 3
= 17 g/mol
Mole of NH₃ =?
Mole = mass /molar mass
Mole of NH₃ = 6.75 / 17
Mole of NH₃ = 0.397 mole
Next, we shall determine the number of mole of NO produced by the reaction of 0.397 mole of NH₃. This can be obtained as follow:
4NH₃ + 5O₂ —> 4NO + 6H₂O
From the balanced equation above,
4 moles of NH₃ reacted to produce 4 moles of NO.
Therefore, 0.397 mole of NH₃ will also react to produce 0.397 mole of NO.
Finally, we shall determine the mass of 0.397 mole of NO. This can be obtained as follow:
Mole of NO = 0.397 mole
Molar mass of NO = 14 + 16 = 30 g/mol
Mass of NO =?
Mass = mole × molar mass
Mass of NO = 0.397 × 30
Mass of NO = 11.9 g
Thus, the mass of NO produced is 11.9 g
