Answer:
Explanation:
- The chemical reaction for cellular respiration is as follows -
C₆H₁₂O₆ ( Glucose ) + 6 O₂ ( Oxygen ) --------------> 6CO₂ ( Carbon dioxide ) + 6H₂O ( Water ) + 38 ATP molecules ( Energy ) .
This is an example of oxidation of carbon .
- The chemical reaction for photosynthesis is as follows -
6CO₂ ( Carbon dioxide ) + 6H₂O ( Water ) --------------> C₆H₁₂O₆( Glucose ) + 6 O₂ ( Oxygen ).
This is an example of reduction of carbon .
<u>Answer:</u> The mass of arsenic found in the sample is 0.25 mg
<u>Explanation:</u>
ppm is the amount of solute (in milligrams) present in kilogram of a solvent. It is also known as parts-per million.
To calculate the ppm of oxygen in sea water, we use the equation:
![\text{ppm}=\frac{\text{Mass of solute}}{\text{Mass of solution}}\times 10^6](https://tex.z-dn.net/?f=%5Ctext%7Bppm%7D%3D%5Cfrac%7B%5Ctext%7BMass%20of%20solute%7D%7D%7B%5Ctext%7BMass%20of%20solution%7D%7D%5Ctimes%2010%5E6)
Both the masses are in grams.
We are given:
Concentration of arsenic = 5 ppm
Mass of sample = 50 g
Putting values in above equation, we get:
![5=\frac{\text{Mass of arsenic}}{50g}\times 10^6\\\\\text{Mass of arsenic}=\frac{5\times 50}{10^6}=0.00025g=0.25mg](https://tex.z-dn.net/?f=5%3D%5Cfrac%7B%5Ctext%7BMass%20of%20arsenic%7D%7D%7B50g%7D%5Ctimes%2010%5E6%5C%5C%5C%5C%5Ctext%7BMass%20of%20arsenic%7D%3D%5Cfrac%7B5%5Ctimes%2050%7D%7B10%5E6%7D%3D0.00025g%3D0.25mg)
<u>Conversion factor used:</u> 1 g = 1000 mg
Hence, the mass of arsenic found in the sample is 0.25 mg
There is a lot of water on earth. If oxygen was very soluble in water, the oceans would absorb and hold the oxygen of the atmosphere and there would be none left for plants and animals.
Hope this help you!!
(p1)(V1)/(T1) = (p2)(V2)/(T2)
(1.00 atm)(V) / (273 + 25K) = (40.0 atm)(V/10) / (273 + T)
273 + T = (40.0)(1/10)(273 + 25K) / (1.00)
T = 919°C