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maksim [4K]
3 years ago
14

Median of 1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20

Mathematics
2 answers:
Andreyy893 years ago
8 0
................... the median is 10.5
Phantasy [73]3 years ago
7 0

Answer:

10.5

Step-by-step explanation:

Find the two middle numbers, add them together and divide them by two if it is an even number. For odd numbers, your median will be the middle number.

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1) Let f(x)=6x+6/x. Find the open intervals on which f is increasing (decreasing). Then determine the x-coordinates of all relat
brilliants [131]

Answer:

1) increasing on (-∞,-1] ∪ [1,∞), decreasing on [-1,0) ∪ (0,1]

x = -1 is local maximum, x = 1 is local minimum

2) increasing on [1,∞), decreasing on (-∞,0) ∪ (0,1]

x = 1 is absolute minimum

3) increasing on (-∞,0] ∪ [8,∞), decreasing on [0,4) ∪ (4,8]

x = 0 is local maximum, x = 8 is local minimum

4) increasing on [2,∞), decreasing on (-∞,2]

x = 2 is absolute minimum

5) increasing on the interval (0,4/9], decreasing on the interval [4/9,∞)

x = 0 is local minimum, x = 4/9 is absolute maximum

Step-by-step explanation:

To find minima and maxima the of the function, we must take the derivative and equalize it to zero to find the roots.

1) f(x) = 6x + 6/x

f\prime(x) = 6 - 6/x^2 = 0 and x \neq 0

So, the roots are x = -1 and x = 1

The function is increasing on the interval (-∞,-1] ∪ [1,∞)

The function is decreasing on the interval [-1,0) ∪ (0,1]

x = -1 is local maximum, x = 1 is local minimum.

2) f(x)=6-4/x+2/x^2

f\prime(x)=4/x^2-4/x^3=0 and x \neq 0

So the root is x = 1

The function is increasing on the interval [1,∞)

The function is decreasing on the interval (-∞,0) ∪ (0,1]

x = 1 is absolute minimum.

3) f(x) = 8x^2/(x-4)

f\prime(x) = (8x^2-64x)/(x-4)^2=0 and x \neq 4

So the roots are x = 0 and x = 8

The function is increasing on the interval (-∞,0] ∪ [8,∞)

The function is decreasing on the interval [0,4) ∪ (4,8]

x = 0 is local maximum, x = 8 is local minimum.

4) f(x)=6(x-2)^{2/3} +4=0

f\prime(x) = 4/(x-2)^{1/3} has no solution and x = 2 is crtitical point.

The function is increasing on the interval [2,∞)

The function is decreasing on the interval (-∞,2]

x = 2 is absolute minimum.

5) f(x)=8\sqrt x - 6x for x>0

f\prime(x) = (4/\sqrt x)-6 = 0

So the root is x = 4/9

The function is increasing on the interval (0,4/9]

The function is decreasing on the interval [4/9,∞)

x = 0 is local minimum, x = 4/9 is absolute maximum.

5 0
2 years ago
Henry had $24.12. His friend Greg had one-
Daniel [21]

Answer: $42.21

Step-by-step explanation:

Henry; $24.12

Gregg; $24.12 / 2= $12.06

Kasey; $ 24.12 / 4= $6.03

$24.12 + $12.06 + $6.03

6 0
3 years ago
Which number line represents all of the values of x for the equations x^2 =100m
statuscvo [17]

Given

\begin{gathered} x^2=100 \\ x=10 \\ x=-10 \end{gathered}

Procedure

3 0
1 year ago
I don't understand, please help.
JulijaS [17]
5y^2-2x/3x^2y^3
 hope you understand its as a fraction.


7 0
3 years ago
Read 2 more answers
How much time is there between 7:45 am today and 3:15 pm tomorrow?
professor190 [17]
4:30 hours ..............
8 0
3 years ago
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