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s2008m [1.1K]
3 years ago
10

(2x-1)(x+4)=0 need this question

Mathematics
2 answers:
eduard3 years ago
6 0

Answer:

x = 1/2 or x = -4

Step-by-step explanation:

Since the product equals zero, use the zero product rule.

(2x - 1)(x + 4) = 0

2x - 1 = 0 or x + 4 = 0

2x = 1   or   x = -4

x = 1/2 or x = -4

Kobotan [32]3 years ago
5 0

Answer: you have 2 solutions for that equation, 1/2 and -4

Step-by-step explanation:

(2x-1)(x+4)=0

2x^2+8x-x-4=2x^2+7x-4

use the formula for quadratic equations

x₁ and x₂  =-(7 (+-)\sqrt49+32)/4=

we have x1= 1/2 and x 2=4

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Luden [163]

Answer:

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8 0
3 years ago
Which of these numbers is divisible by 8,,, 7116 4309 ,,,4136,,, 9406
Nikolay [14]


4136/8= 517

The others
7116/8=889.5
4309/8=538.625
9406/8=1175.75
4 0
3 years ago
Read 2 more answers
(x-y) (x-1,y+3) (I need the answer pls)
SVEN [57.7K]

Answer:

x² - 2xy + 3x + y² - 3y

Step-by-step explanation:

1: Multiply the second parentheses by each term from the first parentheses

X x(x - 1 y + 3) - y x (x - 1y + 3)

2: Distribute x through parentheses

4 0
3 years ago
Complete the square to rewrite x^2+y^2+2x+6y-6=0 in graphing form
Ksivusya [100]

Answer:

(x + 1)² + (y + 3)² = 16

Step-by-step explanation:

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k) are the coordinates of the centre and r is the radius

Given

x² + y² + 2x + 6y - 6 = 0

Collect the x and y terms together and add 6 to both sides

x² + 2x + y² + 6y = 6

To complete the square

add ( half the coefficient of the x/ y terms )² to both sides

x² + 2(1)x + 1 + y² + 2(3)y + 9 = 6 + 1 + 9

(x + 1)² + (y + 3)² = 16

with centre = (- 1, - 3) and r = \sqrt{16} = 4

4 0
3 years ago
P and Q are two points on the line x - y + 1 = 0 and are at distance 5 from the origin. Find the area of the triangle OPQ. ​
Alecsey [184]

Answer:

P and Q are two points on the line x-y+1=0 and are at a distant of 5 units from the origin. Find the area of triangle POQ.

Step-by-step explanation:

P and Q are the intersection points of

x-y+1 = 0 and the circle x^2 + y^2 = 25

sub y = x+1 into the circle

x^2 + (x+1)^2 = 25

x^2 + x^2 + 2x + 1 - 25 = 0

x^2 + x - 12 = 0

(x+4)(x-3) = 0

x = 3 or x = -4

y = 4 or y = -3

so P(3,4) and Q(-4,3) are our two points

Height of triangle.

h = |0 - 0 + 1|/√2 = 1/√2

PQ = √( (-7)^2 + 1^2) = √50 = 5√2

area POQ = (1/2)(1/√2)(5√2) = 5/2 square units

hope this helped

7 0
2 years ago
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