Answer:
Follows are the solution to the given point:
Step-by-step explanation:
In point a:
¬∃y∃xP (x, y)
∀x∀y(>P(x,y))
In point b:
¬∀x∃yP (x, y)
∃x∀y ¬P(x,y)
In point c:
¬∃y(Q(y) ∧ ∀x¬R(x, y)) 
∀y(> Q(y) V ∀ ¬ (¬R(x,y)))
∀y(¬Q(Y)) V ∃xR(x,y) )
In point d:
¬∃y(∃xR(x, y) ∨ ∀xS(x, y))
∀y(∀x>R(x,y)) 
∃x>s(x,y))
In point e:
¬∃y(∀x∃zT (x, y, z) ∨ ∃x∀zU (x, y, z))
∀y(∃x ∀z)>T(x,y,z) ∀x ∃z> V (x,y,z))
If the place to the right of where you are rounding is 5 or higher, you have to round up. If it is 4 or lower, you have to round down. In the hundreds place, there is a 4. That's lower than 5 meaning that you round down/stay. So, the nearest thousands place is 3,000.
So using a calculator this question is really easy 125,000x 1.35 ^10 =.
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Answer:
Step-by-step explanation:
Total Weight of the package = weight of product + weight of box
Weight of empty box =0.88lb
Total weight of the box is =7.24lb
Let Weight of product inside box=w
Let wet of empty box =y
Total weight = F
Then,
F=y+w
Since F=7.24lb. y=0.88
Then, w=F-y
w=7.24-0.88
w=6.36lb
The weight of the product is 6.36lb
I do not have an answer for that, but you should try looking for that on google or yahoo answers.
