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3 years ago

Make y the subject of the formula:A = xy + yz

Mathematics

1 answer:

Vedmedyk [2.9K]3 years ago

5 0

A=xy+yz
A=y*(x+z)
y=A/(x+z)

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You have prices to rev

Alex17521 [72]

Answer:

34 minutes

Step-by-step explanation:

Given

$Time\ Spent = 6$

$Phone\ Calls = 40$

Required

Number of minutes left to spend (x)

Since there's only 1 minute left to spend on every other call;

Time left = x * 1

Time left = x

The required can further be calculated using:

$Time\ Spent + Time\ Left = Phone\ Calls$

This gives:

$6 + x = 40$

Subtract 6 from both sides

$x = 40 - 6$

$x = 34$

<em>Hence, there are 34 minutes left to spend</em>

8 0

3 years ago

Kelsey has 1/3 of a Hershey Bar. Eric wants 3/5 of this amount, How much will Eric get?

Ainat [17]

Answer:

1/5

Step-by-step explanation

1/3= 0.333333333

3/5 of 0.333333333= 0.2

0.2 as a fraction is 1/5

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3 years ago

Dilate D(7,4) by a scale factor of k = 3

Artemon [7]

Answer: (21,12)

Step-by-step explanation:

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3 years ago

What is cot x(sin^2x+cos^2x)

shusha [124]

Answer:

cot(x)

Step-by-step explanation:

$cot\theta(sin^2\theta+cos^2\theta)$

$cot\theta(1)$

$cot\theta$

Recall the Pythagorean Identity $sin^2x+cos^2x=1$

6 0

2 years ago

Approximate the integral integral integral integral f(x, y) dA by dividing the rectangle R with vertices (0, 0), (4, 0), (4, 2),

amm1812

Answer:

Step-by-step explanation:

Approximate the integral $\int\int\limits_R {f(x,y)} \, dA$ by dividing the region $R$ with vertices (0,0),(4,0),(4,2) and (0,2) into eight equal squares.

Find the sum $\sum\limits^8_{i=1}f(x_i,y_i)\delta A_i$

Since all are equal squares, so $\delta A_i=1$ for every $i$

$\sum\limits^8_{i=1}f(x_i,y_i)\delta A_i=f(x_1,y_1)\delta A_1+f(x_2,y_2)\delta A_2+f(x_3,y_3)\delta A_3+f(x_4,y_4)\delta A_4+f(x_5,y_5)\delta A_5+f(x_6,y_6)\delta A_6+f(x_7,y_7)\delta A_7+f(x_8,y_8)\delta A_8\\\\=f(0.5,0.5)(1)+f(1.5,0.5)(1)+f(2.5,0.5)(1)+f(3.5,0.5)(1)+f(0.5,1.5)(1)+f(1.5,1.5)(1)+f(2.5,1.5)(1)+f(3.5,1.5)(1)\\\\=0.5+0.5+1.5+0.5+2.5+0.5+3.5+0.5+0.5+1.5+1.5+1.5+2.5+1.5+3.5+1.5\\\\=24$

Thus, $\sum\limits^8_{i=1}f(x_i,y_i)\delta A_i=24$

Evaluating the iterate integral $\int\limits^4_0 \int\limits^2_0 {(x+y)} \, dydx=\int\limits^4_0 {[xy+\frac{y^2}{2} ]}\limits^2_0 \, dx =\int\limits^4_0 {[2x+2]}dx\\\\=[x^2+2x]\limits^4_0=24.$

Thus, $\int\limits^4_0 \int\limits^2_0 {(x+y)} \, dydx=24$

7 0

3 years ago