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UkoKoshka [18]
2 years ago
8

Reporting cheating What proportion of students are willing to report cheating by other students? A student project put this ques

tion to an SRS of 172 undergraduates at a large university: ""You witness two students cheating on a quiz. Do you go to the professor?"" Only 19 answered ""Yes.""12
Mathematics
1 answer:
KonstantinChe [14]2 years ago
7 0

Answer:

0.1105

Step-by-step explanation:

We know that question about reporting a cheating is asked to 172 students.

So the sample size would be n=172.

Out of 172 undergraduate students only 19 students answered "yes". It means that only 19 out of 172 students are willing to report cheating and so x=19.

According to definition of proportion

proportion=number of favorable outcome/total number of outcome

p=x/n

we are given that x=19 and n=172 so,

p=19/172=0.1105.

Hence according to given data 11.05% of students are wiling to report cheating by other students.

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You want to find P(\text{no exercise}\mid\text{woman}); that is, given that you randomly choose from the pool of women, the probability that she does not exercise.

By definition of conditional probability,

P(\text{no exercise}\mid\text{woman})=\dfrac{P(\text{no exercise AND woman})}{P(\text{woman})}

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A simpler way of doing this is to look at what's called the marginal distribution of women in the table. Basically this comes down to ignoring all but the data pertaining to the women. There's a total of 496 women, and 341 of them do not exercise. So the probability that a given woman does not exercise is 341/496.

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3 years ago
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Step-by-step explanation:

See the step-by-step solution in the picture attached below.

I hope this answer will help you. Have a nice day !

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