HELP ME PLEASE! Graph x < 2.
1 answer:
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So here are the rules of horizontal asymptotes:
- Degree of Numerator > Degree of Denominator: No horizontal asymptote
- Degree of Numerator = Degree of Denominator:
- Degree of Numerator < Degree of Denominator: y = 0
Looking at the rational function, since the degree of the numerator is 2 and the degree of the denominator is 1 (and 2 > 1), this means that <u>this function has no horizontal asymptote.</u>
Answer:
1. The equation represent an exponential decay
2. The rate of the exponential decay is -3×2.5ˣ·㏑(2.5)
Step-by-step explanation:
When a function a(t) = a₀(1 + r)ˣ has exponential growth, the logarithm of x grows with time such that;
log a(t) = log(a₀) + x·log(1 + r)
Hence in the equation -3 ≡ a₀, (1 + r) ≡ 2.5 and y ≡ a(t). Plugging in the values in the above equation for the condition of an exponential growth, we have;
log y = log(-3) + x·log(2.5)
Therefore, since log(-3) is complex, the equation does not represent an exponential growth hence the equation represents an exponential decay.
The rate of the exponential decay is given by the following equation;
Hence the rate of exponential decay is -3×2.5ˣ × ㏑(2.5)