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faust18 [17]
3 years ago
15

A museum gift shop manager wants to put 1,644 polished rocks into small bags to sell as souvenirs. If the shop manager wants to

put 13 rocks in each bag, how many complete bags can be filled? How many rocks will be left over?
Mathematics
1 answer:
klemol [59]3 years ago
3 0
You’ll need to divide 1,644 and 13 since the manager wants to put 1,644 polished rocks into small bags. And 13 rocks is how much will be in each bag. So you’ll do 1,644/ 15 = 109 with 6 left over. Hope it’s correct :)
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Step-by-step explanation:

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What value of n makes the equation true? (2x^9y^n)(4x^2y^10)=8x^11y^20
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Hi there! The answer is n = 10.

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As you see at the powers of x, we need to add the exponents of the power we when multiply them.
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3 years ago
Read 2 more answers
Which of the following functions f : {0, 1, 2, 3} ! {0, 1, . . . , 7} are one-to-one?
allsm [11]

Answer:

1. No.

f(0)=0\\1^2=1; \text{then } f(1)=1\\2^2=4\equiv 4 \text{ mod 8}; \text{then } f(2)=4\\3^2=9\equiv 1 \text{mod 8 }; \text{then } f(3)=1

Since f(1)=f(3) and 1\neq 3 then f isn't one-to-one.

2. No

f(0)=0\\1^3=1\equiv 1\text{ mod 8}; \text{then } f(1)=1\\2^3=8\equiv 0\text{ mod 8}; \text{then } f(2)=0\\3^3=27\equiv 3 \text{ mod 8}; \text{then } f(3)=3

Since f(0)=f(2) and 0\neq 2 then f isn't one-to-one.

3. No

0^3-8=-8\equiv 0\text{ mod 8}; \text{then } f(0)=0\\1^3-8=-7\equiv 1\text{ mod 8}; \text{then } f(1)=1\\2^3-8=0\equiv 0 \text{ mod 8}; \text{then } f(2)=0\\3^3-8=27-8=19\equiv 3 \text{ mod 8}; \text{then } f(3)=3\\

Since f(0)=f(2) and 0\neq 2 then f isn't one-to-one.

4. Yes

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Since f(0)\neq f(1)\neq f(2) \neq f(3), then f is one-to-one

5. Since f(1)=f(3) and 1\neq 3 then, f isn't one-to-one

3 0
3 years ago
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