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andrew11 [14]
4 years ago
12

What is the value of the exponential expression below? 16^1/2

Mathematics
1 answer:
Trava [24]4 years ago
4 0

Answer:

4

Step-by-step explanation:

Using the rule of exponents/ radicals

a^{\frac{m}{n} } ⇔ (\sqrt[n]{a})^m, thus

16^{\frac{1}{2} } = \sqrt{16} = 4

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What are the excluded values of x for x + 1/ x^2-1
Snezhnost [94]

The excluded values of x are x=1 and x=-1

Explanation:

The given expression is \frac{x+1}{x^2-1}

The excluded values are the values in the fraction which makes the denominator equal to 0.

Thus, from the definition of excluded values, let us equate the denominator to 0.

Hence, we have,

x^{2} -1=0

Adding both sides of the equation by 1, we get,

x^{2} =1

Taking square root on both sides of the equation, we get,

x=\sqrt{1}

Simplifying, we get,

x=\pm1

Thus, the excluded values of x are x=1 and x=-1

6 0
4 years ago
10^3*10^4/10^5 write the expression as a single power of ten
Triss [41]
10 and try using photomath it helps.
3 0
3 years ago
One-half a number minus 6 is 4. what is the number​
tatyana61 [14]

Answer:

the answer is 20

Step-by-step explanation:

20/2= 10. 10-6= 4.

8 0
3 years ago
PLEASE ANSWER! (BRAINLIEST)
gavmur [86]

First, find the distance AB by the formula:

AB=\sqrt{(x_B-x_A)^2+(y_B-y_A)^2}.

If A(0,-7) and B(8,8), then

AB=\sqrt{(8-0)^2+(8-(-7))^2}=\sqrt{8^2+15^2}=\sqrt{64+225}=\sqrt{289}=17.

Dilating polygon ABCD by a scale factor of 2 with the center of dilation at the origin to create polygon A′B′C′D′, you increase the distance AB twice, A'B'=2AB. Thus, A'B'=2·17=34 units.

Answer: AB=17 units, A'B'=34 units.


8 0
4 years ago
How do i write the product of q and 11 as an algebraic expression
san4es73 [151]

Answer:

since the product meaning multiplication, it basically means 11 (q) which is 11q.

3 0
3 years ago
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