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riadik2000 [5.3K]
3 years ago
7

I need help is it A B C or D

Mathematics
1 answer:
Vesna [10]3 years ago
7 0
Its (C) i hope this helps you
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Write an equation of the line that passes through the points (-2,-3) and (1-3)
Ronch [10]

\bf (\stackrel{x_1}{-2}~,~\stackrel{y_1}{-3})\qquad (\stackrel{x_2}{1}~,~\stackrel{y_2}{-3}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{-3}-\stackrel{y1}{(-3)}}}{\underset{run} {\underset{x_2}{1}-\underset{x_1}{(-2)}}}\implies \cfrac{-3+3}{1+2}\implies \cfrac{0}{3}\implies 0

\bf \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-3)}=\stackrel{m}{0}[x-\stackrel{x_1}{(-2)}] \\\\\\ y+3=0\implies y=-3

7 0
3 years ago
Read 2 more answers
explain how to find the area of a composite figure. (you do not need to know what shapes, just explain what you do to solve for
OlgaM077 [116]

Answer: A composite figure is made up of simple geometric shapes. To find the area of a composite figure or other irregular-shaped figure, divide it into simple, non overlapping figures. Find the area of each simpler figure, and then add the areas together to find the total area of the composite figure.

7 0
3 years ago
What is an equation of the line that passes through the points (1, 2) and (2, -1)?
Alex Ar [27]

Answer:

slope(m) = y2 -y1/ x2 - x1

m = -1 - 2/ 2 - 1

m = -3/1 ; m = -3

using the formula y -y1 = m(x - x1)

y - 2 = -3( x -1)

y -2 = -3x +3

collect like terms

3 +2 = y + 3x

y + 3x = 5

y = -3x + 5( y = mx + c)

equation of the line= y = -3x + 5

8 0
2 years ago
Prove the formula that:
azamat

Step-by-step explanation:

Given: [∀x(L(x) → A(x))] →

[∀x(L(x) ∧ ∃y(L(y) ∧ H(x, y)) → ∃y(A(y) ∧ H(x, y)))]

To prove, we shall follow a proof by contradiction. We shall include the negation of the conclusion for

arguments. Since with just premise, deriving the conclusion is not possible, we have chosen this proof

technique.

Consider ∀x(L(x) → A(x)) ∧ ¬[∀x(L(x) ∧ ∃y(L(y) ∧ H(x, y)) → ∃y(A(y) ∧ H(x, y)))]

We need to show that the above expression is unsatisfiable (False).

¬[∀x(L(x) ∧ ∃y(L(y) ∧ H(x, y)) → ∃y(A(y) ∧ H(x, y)))]

∃x¬((L(x) ∧ ∃y(L(y) ∧ H(x, y))) → ∃y(A(y) ∧ H(x, y)))

∃x((L(x) ∧ ∃y(L(y) ∧ H(x, y))) ∧ ¬(∃y(A(y) ∧ H(x, y))))

E.I with respect to x,

(L(a) ∧ ∃y(L(y) ∧ H(a, y))) ∧ ¬(∃y(A(y) ∧ H(a, y))), for some a

(L(a) ∧ ∃y(L(y) ∧ H(a, y))) ∧ (∀y(¬A(y) ∧ ¬H(a, y)))

E.I with respect to y,

(L(a) ∧ (L(b) ∧ H(a, b))) ∧ (∀y(¬A(y) ∧ ¬H(a, y))), for some b

U.I with respect to y,

(L(a) ∧ (L(b) ∧ H(a, b)) ∧ (¬A(b) ∧ ¬H(a, b))), for any b

Since P ∧ Q is P, drop L(a) from the above expression.

(L(b) ∧ H(a, b)) ∧ (¬A(b) ∧ ¬H(a, b))), for any b

Apply distribution

(L(b) ∧ H(a, b) ∧ ¬A(b)) ∨ (L(b) ∧ H(a, b) ∧ ¬H(a, b))

Note: P ∧ ¬P is false. P ∧ f alse is P. Therefore, the above expression is simplified to

(L(b) ∧ H(a, b) ∧ ¬A(b))

U.I of ∀x(L(x) → A(x)) gives L(b) → A(b). The contrapositive of this is ¬A(b) → ¬L(b). Replace

¬A(b) in the above expression with ¬L(b). Thus, we get,

(L(b) ∧ H(a, b) ∧ ¬L(b)), this is again false.

This shows that our assumption that the conclusion is false is wrong. Therefore, the conclusion follows

from the premise.

15

5 0
3 years ago
There is 4.8% sales tax on all clothing items purchased. Danielle wants to buy a shirt, which costs $18.95. Danielle figures tha
inysia [295]

Answer:

Yes ,is a reasonable amount. If she has $20 she will have enough to buy the shirt

Step-by-step explanation:

we know that

The total amount is equal to the price of the shirt plus the sales tax

we have that

100\%+4.8\%=104.8\%=104.8/100=1.048

Multiply 1.048 by the cost of the shirt

\$18.95(1.048)=\$19.86

Compare

\$19.86 < \$20

therefore

Yes ,is a reasonable amount. If she has $20 she will have enough to buy the shirt

5 0
3 years ago
Read 2 more answers
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