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Mama L [17]
3 years ago
15

i am a number beetween 20 and 30 who is divisible by 2 4 and 7. I am an even number as well who am I?

Mathematics
2 answers:
miskamm [114]3 years ago
7 0

Answer:

28

Step-by-step explanation:

28/2=14

28/4=7

28/7=4

28 is an even number

Varvara68 [4.7K]3 years ago
5 0

Step-by-step explanation:

<em>28 is the answer</em>

<em>2</em><em>8</em><em> </em><em>is</em><em> </em><em>a</em><em> </em><em>num</em><em>ber</em><em> </em><em>bet</em><em>ween</em><em> </em><em>2</em><em>0</em><em> </em><em>and</em><em> </em><em>3</em><em>0</em>

<em>and</em><em> </em><em>divisible</em><em> </em><em>by</em>

<em>2</em><em>8</em><em>/</em><em>2</em><em>=</em><em>1</em><em>4</em>

<em>2</em><em>8</em><em>/</em><em>4</em><em>=</em><em>7</em>

<em>2</em><em>8</em><em>/</em><em>7</em><em>=</em><em>4</em>

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<h2>Answer: 816 years</h2>

This problem can be solved using the <u>Radioactive Half Life Formula: </u>

<u />

A=A_{o}.2^{\frac{-t}{h}}   (1)

Where:

A=2.7g is the final amount of the material

A_{o}=10g is the initial amount of the material

t is the time elapsed  (the quantity we are asked to find)

h=432y is the half life of americium-241

Knowing this, let's find t from (1):

2.7g=(10g).2^{\frac{-t}{432y}}  

\frac{2.7g}{10g}=2^{\frac{-t}{432y}}  

0.27g=2^{\frac{-t}{432y}}  

Applying natural logarithm in both sides:

ln(0.27g)=ln(2^{\frac{-t}{432y}})  

-1.309=-\frac{t}{432y}ln(2)  

-t=\frac{(-1.309)(432y)}{0.693}  

<u></u>

<u>Finally:</u>

t=816y

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