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valina [46]
3 years ago
10

Can anyone help me whats is -867-(45)7{76+78}=

Mathematics
1 answer:
konstantin123 [22]3 years ago
4 0
It is -49,377 glad to help!!!
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Find the solution set of the quadratic equation over the set of complex numbers.
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Step 2: Subtract 10 from the 8 and the number by itself cause whatever you do to one side you must do to the other. so the equation should look like this after the second step 12x + -2 = 0 because we subtracted the 10 and the 8.

Step 3: Now we must add the 2 to both sides because we have to do the inverse operation in this problem so once we've done this it should end up looking like this after the 3rd step 12x = 2 because the 2 was a negative.

Step 4: the final step we must divide since an anytime we have a number next to a variable it means multiply but since were using order of operations we have to do the opposite/inverse operation in this problem and we would divide 12 by 2 and get our final answer as x = -6 because the 12 would cancel itself out leaving us with 2 divided by 12 which is 0.16 or -6 depending on if you want it simplified or not the simplified answer would be 0.16 and the non simplified version would be -6
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3 years ago
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How to find binary equivalent of a number.
nasty-shy [4]
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The number of dollars per month it costs you to own a car is a function of the number of kilometers per month you drive it. Base
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Work out the height of a parallelogram with a base of 10m and an area of 60m2
noname [10]
Area formula of a parallelogram is
        A = base x height

Given are the
Area = 60 m² and base = 10 m

 Substitute the given:

60 = 10h  (divide by 10 to find value of h)
\frac{60}{10} = \frac{10h}{10}  (10 and 10 cancels out)

h = 6
The height of a parallelogram with a base of 10m and an area of 60m² is 6m

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3 years ago
on a deposit of $4,000 that earns 8% compound interest compounded annually how much will you have after 2 years​
NikAS [45]

\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$4000\\ r=rate\to 8\%\to \frac{8}{100}\dotfill &0.08\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &2 \end{cases} \\\\\\ A=4000\left(1+\frac{0.08}{1}\right)^{1\cdot 2}\implies A=4000(1.08)^2\implies A=4665.6

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3 years ago
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