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Orlov [11]
2 years ago
6

Find the measure of k

Mathematics
1 answer:
Sedaia [141]2 years ago
8 0
The whole triangle and the triangle with the angle K are both isosceles triangle which means two angles are equal.
The total triangle angle is 180. Using this you can find the K.

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For which inequality is {x | x R, x > 6} the solution set?
CaHeK987 [17]

Answer:

C

Step-by-step explanation:

<em>B: 2X + 12 > 3</em>

2x > -9

x> -9/2

<em>C: 2X - 5 > 7</em>

2x > 12

x > 6

<em>D: 2x - 6 > 24</em>

2x > 30

x > 15

Hope this helps ^-^

6 0
2 years ago
Minimum and maximum value of 2n^2+5n-25=0
Alborosie
Equations don't have minimum or maximum, functions do.

Function y=2n^2+5n-25 has minimum -28.125, has no maximum.
8 0
2 years ago
How do I express 540 as a product of prime factors
aksik [14]
540=
54*10=
6*9*2*5=
2*3*3*3*2*5=
2*2*3*3*3*5 or in exponential form
(2²)(3³)(5)
6 0
3 years ago
Read 2 more answers
In Triangle XYZ, measure of angle X = 49° , XY = 18°, and
marissa [1.9K]

Answer:

There are two choices for angle Y: Y \approx 54.987^{\circ} for XZ \approx 15.193, Y \approx 27.008^{\circ} for XZ \approx 8.424.

Step-by-step explanation:

There are mistakes in the statement, correct form is now described:

<em>In triangle XYZ, measure of angle X = 49°, XY = 18 and YZ = 14. Find the measure of angle Y:</em>

The line segment XY is opposite to angle Z and the line segment YZ is opposite to angle X. We can determine the length of the line segment XZ by the Law of Cosine:

YZ^{2} = XZ^{2} + XY^{2} -2\cdot XY\cdot XZ \cdot \cos X (1)

If we know that X = 49^{\circ}, XY = 18 and YZ = 14, then we have the following second order polynomial:

14^{2} = XZ^{2} + 18^{2} - 2\cdot (18)\cdot XZ\cdot \cos 49^{\circ}

XZ^{2}-23.618\cdot XZ +128 = 0 (2)

By the Quadratic Formula we have the following result:

XZ \approx 15.193\,\lor\,XZ \approx 8.424

There are two possible triangles, we can determine the value of angle Y for each by the Law of Cosine again:

XZ^{2} = XY^{2} + YZ^{2} - 2\cdot XY \cdot YZ \cdot \cos Y

\cos Y = \frac{XY^{2}+YZ^{2}-XZ^{2}}{2\cdot XY\cdot YZ}

Y = \cos ^{-1}\left(\frac{XY^{2}+YZ^{2}-XZ^{2}}{2\cdot XY\cdot YZ} \right)

1) XZ \approx 15.193

Y = \cos^{-1}\left[\frac{18^{2}+14^{2}-15.193^{2}}{2\cdot (18)\cdot (14)} \right]

Y \approx 54.987^{\circ}

2) XZ \approx 8.424

Y = \cos^{-1}\left[\frac{18^{2}+14^{2}-8.424^{2}}{2\cdot (18)\cdot (14)} \right]

Y \approx 27.008^{\circ}

There are two choices for angle Y: Y \approx 54.987^{\circ} for XZ \approx 15.193, Y \approx 27.008^{\circ} for XZ \approx 8.424.

6 0
3 years ago
Math question screen shot down below
Oksanka [162]

Answer:

The correct answer is A, Point P

Step-by-step explanation:

since the additive inverse of 2 is -2 because -2 + 2 = 0 the correct choice must be choice A, Point P.

8 0
3 years ago
Read 2 more answers
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