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3 years ago

12

A tire company produced a batch of 6 comma 700 tires that includes exactly 250 that are defective.

1 answer:

mezya [45]3 years ago

8 0

the probability that if you pick only one, it's defective, is 250/6700

Therefore, the probability that one is not defective is 6450/6700

a. You want all 4 to not be defective: (6450/6700)^4

b. all 100 have to be not defective: (6450/6700)^100

If you type this into a calculator, you will get about 0.022, so a probability of 2 % that all of them are not defective. As this is a very small probability, the outlet should plan with returned tires.

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A student is 7 years old. If you triple the teachers age and add the student's age the answer is 163. How old is the teacher?

pogonyaev

Answer:

52

Step-by-step explanation:

We can write this out as an equation. Let's say that the teacher's age is x. Triple the teachers age plus the students age is 163, which can be written out as:

$3x + 7 = 163$

We want to isolate the variable, so subtract 7 from both sides. This gives us:

$3x = 156$

Finally, we divide both sides by 3, giving:

$x=52$

So the teacher is 52 years old.

Hope this helps!

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cestrela7 [59]

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3 years ago

Use the compound interest formula A =P(1 + r) t and the given information to solve for r.

Dmitry [639]

Answer:

Rounding to nearest hundredths gives us r=0.06.

So r is about 6%.

Step-by-step explanation:

So we are given:

$A=P(1+r)^t$

where

$A=2300$

$P=1600$

$t=6$ .

$A=P(1+r)^t$

$2300=1600(1+r)^6$

Divide both sides by 1600:

$\frac{2300}{1600}=(1+r)^6$

Simplify:

$\frac{23}{16}=(1+r)^6$

Take the 6th root of both sides:

$\sqrt[6]{\frac{23}{16}}=1+r$

Subtract 1 on both sides:

$\sqrt[6]{\frac{23}{16}}-1=r$

So the exact solution is $r=\sqrt[6]{\frac{23}{16}}-1$

Most likely we are asked to round to a certain place value.

I'm going to put my value for r into my calculator.

r=0.062350864

Rounding to nearest hundredths gives us r=0.06.

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Answer:

26 2/3 minutes: The two boys meet after 26 2/3 minutes

Step-by-step explanation:

Distance covered by Jim = Distance covered by Bob

(5 mph)(t) = (8 mph)(t - 10)

Simplify this by performing the indicated multiplication:

(5 mph)(t) = (8 mph)(t) - 80 mi

or:

80 mi = (3 mph)(t), or

80 mi

t = ----------- = 26 2/3 minutes

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