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Effectus [21]
2 years ago
5

Can you you help me with this question plz

Mathematics
2 answers:
Lynna [10]2 years ago
5 0

Answer:

4^6

Step-by-step explanation:

:)rjjsbehesbbehsbs

iVinArrow [24]2 years ago
3 0

Answer:

Step-by-step explanation:

4 exposant 6

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3c + 5d = 7d – 6c, solve for d
liubo4ka [24]

Answer:

-3c+12d

Step-by-step explanation:

3 0
3 years ago
Freddy wants an average grade of 93 from his four algebra exams. The scores for his first three exams are 94, 89, and 96. What g
White raven [17]
He would need a 93% on his fourth exam.

94+89+96+93= 372, 372 divided by 4= 93
8 0
3 years ago
Susan runs each lap in 5 minutes. She will run less than 11 laps today. What are the possible numbers of minutes she will run to
galina1969 [7]

Answer:

less than 55 minutes

Step-by-step explanation:

11 laps at 5 minutes per lap is 55 minutes.

Since she will run fewer than 11 laps, she will run less than 55 minutes.

4 0
3 years ago
Read 2 more answers
PLEASE HELP ME
denis23 [38]

Answer:

(1) The possible outcomes are: X = {0, 1, 2, 3}.

(2) The number of times should Hartley spin a difference of 1 is 36.

(3) The number of times should Hartley spin a difference of 0 is 24.

Step-by-step explanation:

The number of sections on the spinner is 4 labelled as {1, 2, 3, 4}.

The total number of spins for each of the spinner is, <em>n</em> = 96.

(1)

The sample space of spinning both the spinners together are:

S = {(1, 1), (1, 2), (1, 3), (1, 4)

      (2, 1), (2, 2), (2, 3), (2, 4)

      (3, 1), (3, 2), (3, 3), (3, 4)

      (4, 1), (4, 2), (4, 3), (4, 4)}

Total = 16.

The possible outcomes are:

X = {0, 1, 2, 3}.

(2)

The sample space with the difference 1 are:

S₁ = {(1, 2), (2, 1), (2, 3), (3, 2), (3, 4), (4, 3)}

n (S₁) = 6

The probability of the difference 1 is:

P(\text{Diff}=1)=\frac{n(S_{1})}{N}=\frac{6}{16}=\frac{3}{8}

The spinners were spinner 96 times.

The expected number of times would Hartley spin a difference of 1 is:

E(\text{Diff}=1)=P(\text{Diff}=1)\times n\\\\=\frac{3}{8}\times 96\\\\=36

Thus, the number of times should Hartley spin a difference of 1 is 36.

(3)

The sample space with the difference 0 are:

S₂ = {(1, 1), (2, 2), (3, 3), (4, 4)}

n (S₂) = 4

The probability of the difference 0 is:

P(\text{Diff}=0)=\frac{n(S_{2})}{N}=\frac{4}{16}=\frac{1}{4}

The spinners were spinner 96 times.

The expected number of times would Hartley spin a difference of 0 is:

E(\text{Diff}=0)=P(\text{Diff}=0)\times n\\\\=\frac{1}{4}\times 96\\\\=24

Thus, the number of times should Hartley spin a difference of 0 is 24.

4 0
3 years ago
By the Triangle Inequality Theorem, if two sides of a triangle have lengths of 6 and 13, what are the possible lengths of the th
murzikaleks [220]
1. You have that two sides of a triangle have lengths of 6 and 13. Then, by the <span>Triangle Inequality Theorem, you have:

 a+b>c
 a+c>b
 b+c>a

 3. Therefore, you have:

 a=6
 b=13

 c<a+b
 c<6+13
 c<19

 4. The difference between a and b should be lesser that c. Then

 a-b<c
 13-6<c
 7<c

 5. Therefore:

 c=x

 7<x<19

 The correct answer is the option B: </span> B. 7<x<19<span>

</span>
5 0
3 years ago
Read 2 more answers
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