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Effectus [21]
2 years ago
5

Can you you help me with this question plz

Mathematics
2 answers:
Lynna [10]2 years ago
5 0

Answer:

4^6

Step-by-step explanation:

:)rjjsbehesbbehsbs

iVinArrow [24]2 years ago
3 0

Answer:

Step-by-step explanation:

4 exposant 6

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How many inches is 11.6 cm
Minchanka [31]
4.567 inches should be the answer
3 0
3 years ago
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50 POINTS/ WILL MARK BRAINLIEST
Nina [5.8K]

Answer:

i think the answer is She replaced both the divisor and the dividend with their reciprocals when changing division to multiplication in step 2.

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8 0
2 years ago
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Si un triángulo tiene una hipotenusa de 15 cm y un cateto que mide 12 cm, ¿cual es la longitud del otro cateto?
BartSMP [9]

Answer:

   

9cm

Explicación:

El teorema de pitagoras nos dice que la hipotenusa al cuadrado es igual a la suma de los catetos al cuadrado:

c^{2} =a^{2} + b^{2}

Donde c es la hipotenusa y a  y b son los catetos.

Por lo cual, podemos reemplazar c por 15cm y a por 12cm :

15^{2} =12^{2} +b^{2}

Finalmente , debemos resolver la ecuación para b, así que b es igual a :

225=144+b^{2} \\225-144=144+b^{2} -144\\81=b^{2} \\\sqrt{81} =b\\9=b

Por lo tanto, la longitud del otro cateto es 9 cm

3 0
2 years ago
Help me please 98 math
luda_lava [24]

Answer:

the least common denominator would have to be 77

Step-by-step explanation:

because the product of 11 and 7 equals 77 but there is nothing less than that that can actually be a COMMON denominator

for example: 7 can be multiplied by numbers to get these out comes //

7,14,21,28,35,42,49,56,63,70,77 and 77 is the only one that 11 can actually equal to that is common with 7

5 0
3 years ago
Solve the equation for x in terms of c
Dovator [93]

solve\:for\:x,\:\frac{2}{3}\left(cx+\frac{1}{2}\right)-\frac{1}{4}=\frac{5}{2}

\mathrm{Add\:}\frac{1}{4}\mathrm{\:to\:both\:sides}

\frac{2}{3}\left(cx+\frac{1}{2}\right)-\frac{1}{4}+\frac{1}{4}=\frac{5}{2}+\frac{1}{4}

\frac{2}{3}\left(cx+\frac{1}{2}\right)=\frac{11}{4}

\mathrm{Multiply\:both\:sides\:by\:}3

3\cdot \frac{2}{3}\left(cx+\frac{1}{2}\right)=\frac{11\cdot \:3}{4}

2cx+1=\frac{33}{4}

\mathrm{Subtract\:}1\mathrm{\:from\:both\:sides}

2cx+1-1=\frac{33}{4}-1

2cx=\frac{29}{4}

\mathrm{Divide\:both\:sides\:by\:}2c

x=\frac{29}{8c}

<h3>Therefore, correct option is C. option.</h3><h3>C. x=29/8c</h3>
8 0
3 years ago
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