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mars1129 [50]
3 years ago
14

6. A hot air balloons each descend 100 feet per minute for 5 minutes. Find the total change in altitude for the hot air balloon.

​
Mathematics
1 answer:
monitta3 years ago
7 0

Answer:

6

Step-by-step explanation:

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Which statement best describes the function represented by the graph??
Novosadov [1.4K]

Answer:

The last one decreasing on the interval (-infinity, 0) where it becomes constant

Step-by-step explanation:

6 0
3 years ago
I need help plzzzzzzzzzzzzzzzzzzzzz
blagie [28]

Answer:

Step-by-step explanation:

Start box

180 = 89+42+x

180-89-42=x

49 = x

2nd box

180 = 84+58+x

180-84-58=x

38 = x

3rd box

180=74+2x

180-74=2x

106/2 = x

53 = x

4th box

180=102+2x

180-102=2x

78/2 = x

39 = x

4th box

180 = 73+81 +x

180-73-81=x

26 = x

5th box

180=2*54+x

180 - 2*54 = x

72 = x

6th box

180=62-2x

180-62=2x

118=2x

118/2=x

59 = x

7th box

180 = 2*68 + x

180-2*68=x

44 = x

3 0
2 years ago
How to convert 18 gallons/1 hour to cups and minutes
Ne4ueva [31]
So there are 2 things you need to convert, the first is the gallons to cups and the second is the hours to minutes. so I like to set it up with numerators and denominators and then multiply the ratios. All same terms will cross out and be opposite of each other. 

(18 gal/1 hour) x (1 hour / 60 minutes), now we have (0.3 gallons/1 minute) we just have to change gallons to cups

(0.3 gallons/ 1 minute) x (4 quarts/1 gallon) x (2 pints/1 quart) x (2 cups/1 pint)

this comes out 4.8 cups/1 minute
8 0
3 years ago
What expression is equivalent to -0.5x - 4?
Assoli18 [71]

Answer:

2x-32

Step-by-step explanation:

You would distribute the 4.

3 0
2 years ago
he life of light bulbs is distributed normally. The variance of the lifetime is 625 and the mean lifetime of a bulb is 540 hours
almond37 [142]

Using the normal distribution, it is found that there is a 0.877 = 87.7% probability of a bulb lasting for at most 569 hours.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean \mu and standard deviation \sigma is given by:

Z = \frac{X - \mu}{\sigma}

  • The z-score measures how many standard deviations the measure is above or below the mean.
  • Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

The mean and the standard deviation are given, respectively, by:

\mu = 540, \sigma = \sqrt{625} = 25

The probability of a bulb lasting for at most 569 hours is the <u>p-value of Z when X = 569</u>, hence:

Z = \frac{X - \mu}{\sigma}

Z = \frac{569 - 540}{25}

Z = 1.16

Z = 1.16 has a p-value of 0.877.

0.877 = 87.7% probability of a bulb lasting for at most 569 hours.

More can be learned about the normal distribution at brainly.com/question/24663213

#SPJ1

8 0
2 years ago
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