All categories

3 years ago

I added a picture : Determine which of the lines, if any, are parallel or perpendicular. Explain.

Mathematics

1 answer:

exis [7]3 years ago

5 0

Answer:

1. line a and c and parallel. line b is perpendicular with line a and c. 2. line b and c and parallel. line a is perpendicular to lines b and c. 3. y= -3x + 3 4. y=(5/3)x - 9

Step-by-step explanation:

To find parallel and perpendicular, make the slope opposite and find b by plugging in the points. Parallel is the same slope.

You might be interested in

If there is a song that is 2 minutes and 58 seconds long and it plays 40 times how long does it play convert answer into seconds

lapo4ka [179]

Answer: I got 7120 seconds

Step-by-step explanation:

There's 178 seconds in the song (for more context, I just converted the 2 minutes into seconds and added it with 58) then I multiplied it by the total amount of times it played (in this case, 40)

Hope this helps

3 0

3 years ago

Read 2 more answers

Jasmine’s age is 4 times her age 10 years ago. Write an equation that represents the statement.

aleksandr82 [10.1K]

Answer:

x + 10 = 4x

Step-by-step explanation:

Let x = her age 10 years ago.

Her age now is x + 10.

x + 10 = 4x

5 0

1 year ago

For which of the following decreasing functions f does (f−1)′(10)=−1/8

Oduvanchick [21]

Recall the inverse function theorem: if f(x) has an inverse, and if f(a) = b and a = f⁻¹(b), then

f⁻¹(f(x)) = x ⇒ (f⁻¹)'(f(x)) • f'(x) = 1 ⇒ (f⁻¹)'(f(x)) = 1/f'(x)

⇒ (f⁻¹)'(b) = 1/f'(a)

Let b = 10. Then pick the function f(x) such that f(a) = 10 and f'(a) = -8 for some number a.

7 0

2 years ago

Consider the differential equation <img src="https://tex.z-dn.net/?f=%20x%5E%7B2%7D%20%20%5Cfrac%7Bdy%7D%7Bdx%7D%20%3D6%20y%5E%7

Nutka1998 [239]

As a Bernoulli equation:

$x^2\dfrac{\mathrm dy}{\mathrm dx}=6y^2+6xy\iff x^2y^{-2}\dfrac{\mathrm dy}{\mathrm dx}-6xy^{-1}=6$

Let $z=y^{-1}\implies\dfrac{\mathrm dz}{\mathrm dx}=-y^{-2}\dfrac{\mathrm dy}{\mathrm dx}$ . The ODE becomes

$-x^2\dfrac{\mathrm dz}{\mathrm dx}-6xz=6$
$x^6\dfrac{\mathrm dz}{\mathrm dx}+6x^5z=-6x^4$
$\dfrac{\mathrm d}{\mathrm dx}[x^6z]=-6x^4$
$x^6z=-6\displaystyle\int x^4\,\mathrm dx$
$x^6z=-\dfrac65x^5+C$
$z=-\dfrac6{5x}+\dfrac C{x^6}$
$y^{-1}=-\dfrac6{5x}+\dfrac C{x^6}$
$y=\dfrac1{\frac C{x^6}-\frac6{5x}}$
$y=\dfrac{5x^6}{C-6x^5}$

With $y(3)=6$ , we get

$6=\dfrac{5(3)^6}{C-6(3)^5}\implies C=\dfrac{4131}2$

so the solution is

$y=\dfrac{5x^6}{\frac{4131}2-6x^5}=\dfrac{10x^6}{4131-12x^5}$

which is valid as long as the denominator is not zero, which is the case for all $x\neq\sqrt[5]{\dfrac{4131}{12}}$ .