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arlik [135]
3 years ago
7

Maths - 7 out of 10 students are boys. If there are 30 students, how many of them are girls? Help me I stuck

Mathematics
1 answer:
GenaCL600 [577]3 years ago
5 0

Answer:

there would be 21 girls

Step-by-step explanation:

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Use this picture to solve for X
Zepler [3.9K]

Answer:

x=2

Step-by-step explanation:

i would set up a system of equation using the pythagorean theorem:

1^2+x^2=z^2

4^2+x^2=y^2

Add up these equations to get:

17+2x^2=y^2+z^2

But notice that

y^2+z^2=5^2

So you can substitute

17+2x^2=25

2x^2=8

x^2=4

x=2

:)

8 0
3 years ago
What is the answer? X/8 - 4 = 15/16
sukhopar [10]

Answer:

<h2>x = 39.5</h2>

Step-by-step explanation:

\dfrac{x}{8}-4=\dfrac{15}{16}\qquad\text{multiply both sides by 8}\\\\8\!\!\!\!\diagup^1\cdot\dfrac{x}{8\!\!\!\!\diagup_1}-(8)(4)=8\!\!\!\!\diagup^1\cdot\dfrac{15}{16\!\!\!\!\!\diagup_2}\\\\x-32=\dfrac{15}{2}\qquad\text{add 32 to both sides}\\\\x-32+32=7.5+32\\\\x=39.5

5 0
4 years ago
Solve for x.<br> 5<br> 10<br> 12<br> 13
zysi [14]

Answer: B)  4 & 1/6

Nice work on getting the correct answer.

============================================================

Explanation:

x is opposite the marked acute angle

5 is opposite the corresponding acute angle

So x and 5 are proportional to each other. We can form the ratio x/5

Similarly, 10 and 12 are proportional to one another. We can form the ratio 10/12.

Set those ratios equal to each other and solve for x

x/5 = 10/12

12x = 5*10 ... cross multiply

12x = 50

x = 50/12 ...... divide both sides by 12

x = (25*2)/(6*2)

x = 25/6

x = (24+1)/6

x = 24/6 + 1/6

x = 4 + 1/6

x = 4 & 1/6 which shows why <u>choice B</u> is the answer.

Side note: 25/6 = 4.167 approximately

8 0
3 years ago
Read 2 more answers
A cafeteria offers oranges, apples , or bananas as it’s fruit option. Find the number of fruit and
Yuri [45]

Question:

A cafeteria offers oranges, apples, or bananas as its fruit option. It offers peas, green beans, or carrots as the vegetable option. Find the number of fruit and vegetable options. If the fruit and the vegetable are chosen at random. what is the probability of getting an orange and carrots? Is it likely or unlikely that a customer would get an orange and carrots?

Answer:

The probability of getting an orange and carrots is \frac{1}{9}

Step-by-step explanation:

The fruits offered in cafeteria = oranges, apples, or bananas.

The vegetables offered in cafeteria  = peas, green beans, or carrots.

There are 3 fruits and 3 vegetables . Therefore the total possible number of  outcomes is  = 3 \cdot 3 =  9

Now the probability of getting an orange and carrots = \frac{1}{9}

The possibility is very unlikely to happen

7 0
4 years ago
Solve. 3n-7+2n=8n+11
Bezzdna [24]
------------------------------------
<span>Question:
</span>------------------------------------<span>
3n - 7 + 2n = 8n + 11

------------------------------------
Combine like terms:
</span>------------------------------------<span>
5n - 7 = 8n + 11

</span>------------------------------------<span>
subtract 8n from both sides:
</span>------------------------------------<span>
-3n - 7 = 11

</span>------------------------------------<span>
Add 7 to both sides
</span>------------------------------------<span>
-3n = 18

</span>------------------------------------
Divide by -3 on both sides:
------------------------------------
n = -6

------------------------------------
Answer: n = -6
------------------------------------
5 0
3 years ago
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