Answer:
99.5
Step-by-step explanation:
398 ÷ 4
Answer: 49.85%
Step-by-step explanation:
Given : The physical plant at the main campus of a large state university recieves daily requests to replace florecent lightbulbs. The distribution of the number of daily requests is bell-shaped ( normal distribution ) and has a mean of 61 and a standard deviation of 9.
i.e.
and 
To find : The approximate percentage of lightbulb replacement requests numbering between 34 and 61.
i.e. The approximate percentage of lightbulb replacement requests numbering between 34 and
.
i.e. i.e. The approximate percentage of lightbulb replacement requests numbering between
and
. (1)
According to the 68-95-99.7 rule, about 99.7% of the population lies within 3 standard deviations from the mean.
i.e. about 49.85% of the population lies below 3 standard deviations from mean and 49.85% of the population lies above 3 standard deviations from mean.
i.e.,The approximate percentage of lightbulb replacement requests numbering between
and
= 49.85%
⇒ The approximate percentage of lightbulb replacement requests numbering between 34 and 61.= 49.85%
So from 98 to 110.92 is just 12.92 extra bucks.
if we take 98 to be the 100%, what is 12.92 off of it in percentage?
Answer:
largest 4 digit number × largest 3 digit number
=9999 × 999
(10000-1)×(1000-1) = (a-b)(c-b)= ac-ab-bc+b^2
10000000-10000-1000+1 = 9989001
Answer:
x = - 1/45.
Step-by-step explanation: