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stepan [7]
3 years ago
14

HELP ASAP PLEASE!!!!

Mathematics
1 answer:
polet [3.4K]3 years ago
4 0

Answer:

bqgsdfgsdfghsdfbvcxbxcvb

Step-by-step explanation:

my grandmother told me the answer

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Winston has just gone grocery shopping. The mean cost for each item in his bag was $2.71. He bought a total of 9 items, and the
sukhopar [10]

The cost of the 9th item is  $3.94

Since the mean cost for the 9 items in his bag was $2.71. Then, the total cost will be: = 9 × $2.71 = $24.39

In order to get the price of the 9th item, we have to calculate the price of all the 8 items given which will be:

$2.01 + $2.20 + $2.68 + $3.59 + $3.12 + $1.64, + $1.75 + $3.46 = $20.45

Therefore, the cost of the 9th item will be:

= $24.39 - $20.45

= $3.94

Read related link on:

brainly.com/question/24562826

3 0
3 years ago
(9•4)•18 = 9•(4•18)<br><br><br> A True <br> B. False
AveGali [126]

Answer:

false

Step-by-step explanation:

7 0
4 years ago
Read 2 more answers
Calculating cos-1 ( help is gladly appreciated :) )
Alekssandra [29.7K]

Answer:

\frac{3\pi}{4}

(Assuming you want your answer in radians)

If you want the answer in degrees just multiply your answer in radians by \frac{180^\circ}{\pi} giving you:

\frac{3\pi}{4} \cdot \frac{180^\circ}{\pi}=\frac{3(180)}{4}=135^{\circ}.

We can do this since \pi \text{ rad }=180^\circ (half the circumference of the unit circle is equivalent to 180 degree rotation).

Step-by-step explanation:

\cos^{-1}(x) is going to output an angle measurement in [0,\pi].

So we are looking to solve the following equation in that interval:

\cos(x)=-\frac{\sqrt{2}}{2}.

This happens in the second quadrant on the given interval.

The solution to the equation is \frac{3\pi}{4}.

So we are saying that \cos(\frac{3\pi}{4})=\frac{-\sqrt{2}}{2} implies \cos^{-1}(\frac{-\sqrt{2}}{2})=\frac{3\pi}{4} since \frac{3\pi}{4} \in [0,\pi].

Answer is \frac{3\pi}{4}.

4 0
3 years ago
Michael's father bought him a 16 foot board to cut into shelves for his bedroom. Michael plans to cut the board into 11 equal pi
andrew-mc [135]
This may not be correct sorry , 16÷11 = 1.454545454545454545454545
6 0
3 years ago
An open top box is to be built with a rectangular base whose length is twice its width and with a volume of 36 ft 3 . Find the d
denpristay [2]

Answer:

The dimensions of the box that minimize the materials used is 6\times 3\times 2\ ft

Step-by-step explanation:

Given : An open top box is to be built with a rectangular base whose length is twice its width and with a volume of 36 ft³.

To find : The dimensions of the box that minimize the materials used ?

Solution :

An open top box is to be built with a rectangular base whose length is twice its width.

Here, width = w

Length = 2w

Height = h

The volume of the box V=36 ft³

i.e. w\times 2w\times h=36

h=\frac{18}{w^2}

The equation form when top is open,

f(w)=2w^2+2wh+2(2w)h

Substitute the value of h,

f(w)=2w^2+2w(\frac{18}{w^2})+2(2w)(\frac{18}{w^2})

f(w)=2w^2+\frac{36}{w}+\frac{72}{w}

f(w)=2w^2+\frac{108}{w}

Derivate w.r.t 'w',

f'(w)=4w-\frac{108}{w^2}

For critical point put it to zero,

4w-\frac{108}{w^2}=0

4w=\frac{108}{w^2}

w^3=27

w^3=3^3

w=3

Derivate the function again w.r.t 'w',

f''(w)=4+\frac{216}{w^3}

For w=3, f''(3)=4+\frac{216}{3^3}=12 >0

So, it is minimum at w=3.

Now, the dimensions of the box is

Width = 3 ft.

Length = 2(3)= 6 ft

Height = \frac{18}{3^2}=2\ ft

Therefore, the dimensions of the box that minimize the materials used is 6\times 3\times 2\ ft

4 0
4 years ago
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