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Mashcka [7]
3 years ago
8

Consider the equation x over 5 minus 2 = 11, where x represents the number of basketball players that have signed up for a new l

eague. What is a possible scenario that would be modeled by this equation? Consider how many teams in the league and the number of players on each team this equation could describe
Mathematics
2 answers:
NeTakaya3 years ago
5 0

My Answer:

x equals the total number of players that signed up. Then you  have to split this into 5 teams. 2 players end up not playing. This leaves you with 11 on each team.

Sample Response:

The equation could model a scenario determining the number of players on each team in a league of five teams, if 2 players have to be taken out of the possible players to be referees and to keep score. There will be 11 players on each team.

Nana76 [90]3 years ago
3 0

finally found it (note by found it I mean I finally found someone with an answer because I couldn't figure it out)

Answer:

The equation could model a scenario determining the number of players on each team in a league of five teams, if 2 players have to be taken out of the possible players to be referees and to keep score. There will be 11 players on each team.

(I am giving credit to  Bre122607 so than they don't delete the answer...)

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Which relation is displayed in this table?
elena-s [515]

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D

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As we can observe from the answers the representation is about the pair of points. We can sort it out by excluding the wrong options.

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5 0
3 years ago
a. Suppose we had $15,192 cash and invested it in the bank at 16 percent interest, how much would you have at the end of 1, 2, 3
Goryan [66]

Answer:

Part a) \$17,622.72

Part b) \$20,442.36

Part c) \$23,713.13

Part d) \$27,507.23

Step-by-step explanation:

we know that  

The compound interest formula is equal to

A=P(1+\frac{r}{n})^{nt}

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest  in decimal

t is Number of Time Periods

n is the number of times interest is compounded per year

Part a) How much would you have at the end of 1 year?

in this problem we have

t=1\ years\\ P=\$15,192\\ r=0.16\\n=1

substitute in the formula above

A=15,192(1+\frac{0.16}{1})^{1*1}=\$17,622.72

Part b) How much would you have at the end of 2 year?

in this problem we have

t=2\ years\\ P=\$15,192\\ r=0.16\\n=1

substitute in the formula above

A=15,192(1+\frac{0.16}{1})^{1*2}=\$20,442.36

Part c) How much would you have at the end of 3 year?

in this problem we have

t=3\ years\\ P=\$15,192\\ r=0.16\\n=1

substitute in the formula above

A=15,192(1+\frac{0.16}{1})^{1*3}=\$23,713.13

Part d) How much would you have at the end of 4 year?

in this problem we have

t=4\ years\\ P=\$15,192\\ r=0.16\\n=1

substitute in the formula above

A=15,192(1+\frac{0.16}{1})^{1*4}=\$27,507.23

5 0
3 years ago
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