Answer:
first piece = 1.88in
second piece= 3.76in
third piece = 26.32in
32 = f + s + t
1st piece = f
2nd piece = s
3rd piece = t
what we know:
s = 2f
t = 2(7f)
32 = f + 2f + 2(7f)
32 = 3f +14f
32 = 17f
f = 1.88
now sub in:
f = 1.88
s = 3.76
t = 26.32
when you add these together you get 31.96, when you round up you get 32 which is the original piece of steel.
Answer:
In bold below.
Step-by-step explanation:
a) Arithmetic sequence with common difference 3 and first term = 2:
nth term = 2 + 3(n - 1)
= 3n -1.
b) Similar to above with common difference 2 and first term = 9.
nth term = 9 + 2(n - 1)
= 2n + 7.
There are 2 unknown terms in this problem
the amount of cement the first team received is termed as 'x' hereafter
the cement the second team received is termed as 'y'
the first team received 50 kg less, the 1st equation is as follows;
x = y - 50 after rearranging
1) x-y = -50
for every hour 150 kg and 200 kg were used by the two teams separately
after three hours first team used up 150*3 = 450 kg
the second team used up 200 * 3 = 600 kg
however the first team had 1.5 times as much as second team had after three hours.
After three hours;
the amount second team had leftover was y - 600
the amount first team had leftover was x - 450
the amount the second team had ,multiplied by 1.5 is equal to what the first team had
we can build the 2nd equation using this information
1.5 * (y-600) = x-450
1.5y - 900 = x - 450
rearrange the equation,
1.5y - x = -450 +900
2) 1.5y - x = 450
add 1st and 2nd equations to eliminate x
1) + 2) (x - y = -50) + (1.5y - x = 450)
1.5y - y = 450 -50
0.5y = 400
y = 400/ 0.5
y = 800 kg
substitute y = 800 in x = y - 50
x = 800 - 50
x = 750 kg
first team received 750 kg and second team received 800 kg
List all the factors.
Factors of 15: 1, 3, 5, 15
Factors of 45: 1, 3, 5, 9, 15, 45
Factors of 90: 1, 2, 3, 5, 6, 9, 10, 15, 18, 30, 45, 90
The common factors of 15, 45, and 90 are 1, 3, 5, and 15.
Answer:

Step-by-step explanation:
<u>Firstly, we'll do prime factorization of these numbers.</u>
70 = 2 × 5 × 7
112 = 2 × 2 × 2 × 2 × 7
<u>So, The Greatest Common Factor can be written as:</u>
GCF = 2 × 7 <u>[Since Only one 2 and one 7 is common]</u>
<u></u>
Hope this helped!
<h2>~AnonymousHelper1807</h2>