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Lelu [443]
3 years ago
8

a. Suppose we had $15,192 cash and invested it in the bank at 16 percent interest, how much would you have at the end of 1, 2, 3

, 4 years, assuming annual compounding?
Mathematics
1 answer:
Goryan [66]3 years ago
5 0

Answer:

Part a) \$17,622.72

Part b) \$20,442.36

Part c) \$23,713.13

Part d) \$27,507.23

Step-by-step explanation:

we know that  

The compound interest formula is equal to

A=P(1+\frac{r}{n})^{nt}

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest  in decimal

t is Number of Time Periods

n is the number of times interest is compounded per year

Part a) How much would you have at the end of 1 year?

in this problem we have

t=1\ years\\ P=\$15,192\\ r=0.16\\n=1

substitute in the formula above

A=15,192(1+\frac{0.16}{1})^{1*1}=\$17,622.72

Part b) How much would you have at the end of 2 year?

in this problem we have

t=2\ years\\ P=\$15,192\\ r=0.16\\n=1

substitute in the formula above

A=15,192(1+\frac{0.16}{1})^{1*2}=\$20,442.36

Part c) How much would you have at the end of 3 year?

in this problem we have

t=3\ years\\ P=\$15,192\\ r=0.16\\n=1

substitute in the formula above

A=15,192(1+\frac{0.16}{1})^{1*3}=\$23,713.13

Part d) How much would you have at the end of 4 year?

in this problem we have

t=4\ years\\ P=\$15,192\\ r=0.16\\n=1

substitute in the formula above

A=15,192(1+\frac{0.16}{1})^{1*4}=\$27,507.23

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Answer:

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3 years ago
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In bold below.

Step-by-step explanation:

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2 years ago
The first team of workers received 50 kg of cement less than the second team. for every hour of work the first team was using 15
stepladder [879]
There are 2 unknown terms in this problem 
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the first team received 50 kg less, the 1st equation is as follows;

x = y - 50    after rearranging 
1) x-y = -50
for every hour 150 kg and 200 kg were used by the two teams separately 
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the second team used up 200 * 3 = 600 kg
however the first team had 1.5 times as much as second team had after three hours. 
After three hours;
the amount second team had leftover was y - 600
the amount first team had leftover was x - 450
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we can build the 2nd equation using this information

1.5 * (y-600) = x-450
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add 1st and 2nd equations to eliminate x 
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8 0
3 years ago
What are the common factors of 15,45 and 90
Nookie1986 [14]
List all the factors.

Factors of 15: 1, 3, 5, 15
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The common factors of 15, 45, and 90 are 1, 3, 5, and 15.
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Mekhanik [1.2K]

Answer:

\huge\boxed{C. \ \ GCF = 2 * 7}

Step-by-step explanation:

<u>Firstly, we'll do prime factorization of these numbers.</u>

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112 = 2 × 2 × 2 × 2 × 7

<u>So, The Greatest Common Factor can be written as:</u>

GCF = 2 × 7    <u>[Since Only one 2 and one 7 is common]</u>

<u></u>

Hope this helped!

<h2>~AnonymousHelper1807</h2>
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