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Mariulka [41]
2 years ago
15

Find the holes

itle="f(x)=\frac{x+3}{(x+1)(x-2)}" alt="f(x)=\frac{x+3}{(x+1)(x-2)}" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
olga55 [171]2 years ago
8 0

Answer:

<h2>           x=-1 and x=2</h2>

Step-by-step explanation:

The "holes" are the x-es where function doesn't exist.

one must not divide by 0, so given function doesn't exis if the denominator is equal 0

The product {(x+1)×(x-2)} is equal 0 if any of factors  {(x+1),(x-2)} is 0, so

x + 1 = 0    or    x - 2 = 0

x = - 1      or    x = 2

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What are three ways to get 256 using exponents
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5 0
3 years ago
target sells tide detergent for $6.75 for 25 fluid ounces. walmart sells tide dergernt for $11.20 for 40 fl.oz. use the unit rat
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Step-by-step explanation:

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4 0
2 years ago
What is the opposite of taking a power of a number called
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Square rooting a number
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3 years ago
An instructor wants to write a test with 25 questions where each question is worth 3, 4, or 5 points based on difficulty. He wan
irakobra [83]

ANSWER

Find out the how many 3, 4, and 5 point questions could there be.

To proof

Let us assume that the 3 points based question be = x

Let us assume that the 4 points based question be = y

Let us assume that the 5 points based question be = z

As given

An instructor wants to write a test with 25 questions

than the equation become in the form

x + y + z = 25

he quiz to be worth a total of 100 points.

than the equation is becomes

3x + 4y + 5z =100

As given

He wants the number of 3-point questions to be 4 less than the number of 4-point questions

x = y -4

Than the three equation are

x + y + z = 25 ,3x + 4y + 5z =100 and x = y -4

put  x = y -4 in the x + y + z = 25 ,3x + 4y + 5z =100

than

2y + z = 29, 7y +5z= 112

multiply 2y + z = 29 by 5 and subtracted 7y +5z= 112

10 y -7y + 5y -5y = 145 -112

3y = 33

y = \frac{33}{3}

y =11

put in the  x = y -4

x = 11-4

x= 7

put the value of x ,y in the x + y + z = 25

7 + 11 +z =25

18 +z = 25

z = 25 -18

z=7

therefore

numbers of the 3 point question be = 7

numbers of the 4 point question be = 11

numbers of the 5 point question be = 7

Hence proved



3 0
3 years ago
What is the constant term in the expression 6 x 3^y + 8x^2 + 5x + 7
serious [3.7K]

Answer:

The constant term is 7

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