Question

Find the holes itle="f(x)=\frac{x+3}{(x+1)(x-2)}" alt="f(x)=\frac{x+3}{(x+1)(x-2)}" align="absmiddle" class="latex-formula">

Answer 1

Answer:

          x=-1 and x=2

Step-by-step explanation:

The "holes" are the x-es where function doesn't exist.

one must not divide by 0, so given function doesn't exis if the denominator is equal 0

The product {(x+1)×(x-2)} is equal 0 if any of factors  {(x+1),(x-2)} is 0, so

x + 1 = 0    or    x - 2 = 0

x = - 1      or    x = 2